Timeline for Sum[expr,{i,0,Infinity}] for power series of cumulative normal distribution gives exponential function?
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Oct 28, 2015 at 6:09 | history | edited | J. M.'s missing motivation♦ | CC BY-SA 3.0 |
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| Sep 12, 2013 at 2:21 | vote | accept | Joel Bosveld | ||
| Sep 12, 2013 at 2:21 | history | edited | Joel Bosveld | CC BY-SA 3.0 |
added 263 characters in body
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| Sep 12, 2013 at 1:49 | comment | added | Joel Bosveld |
I repeated in a blank notebook, and I also found it didn't evaluate. ?g showed that there was some cruft left over that was causing the sum to evaluate.
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| Sep 11, 2013 at 17:01 | answer | added | b.gates.you.know.what | timeline score: 1 | |
| Sep 11, 2013 at 13:34 | comment | added | Eckhard | On my Linux, v8.0 the indefinite same does not evaluate either. | |
| Sep 11, 2013 at 12:43 | comment | added | ybeltukov | On my Linux, V 9.0.1 I've got the same result as Nasser. Do you perform it on a fresh kernel? | |
| Sep 11, 2013 at 12:12 | comment | added | Joel Bosveld | @Nasser Thanks for the comment, I've updated the question saying that it was tested on Mathematica 9.01 on Linux. | |
| Sep 11, 2013 at 12:10 | history | edited | Joel Bosveld | CC BY-SA 3.0 |
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| Sep 11, 2013 at 10:12 | comment | added | Jacob Akkerboom |
Hm, strangely Mathematica does simplify Sum[Piecewise[{{1, Mod[i, 2] == 0}}], {i, 0, n}] but not Sum[Piecewise[{{i, Mod[i, 2] == 0}}], {i, 0, n}].
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| Sep 11, 2013 at 7:57 | comment | added | Nasser | on V 9.01 on windows, the sum does not evaluate. I copied what you had there. screen shot: !Mathematica graphics it always helps to say what version and platform you are using. | |
| Sep 11, 2013 at 6:43 | review | First posts | |||
| Sep 11, 2013 at 7:42 | |||||
| Sep 11, 2013 at 6:26 | history | asked | Joel Bosveld | CC BY-SA 3.0 |
