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removed function defintion due to some pure math subtle issues over my head
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Nasser
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z[t_] := Exp[I t];
dt = D[z[t], t]
Integrate[(1/z[t]) dt, {t, 0, 2 Pi}]

Mathematica graphics

Or if you do not want to use functions, use direct expressions:

z = Exp[I t];
dtdz = D[z, t];
Integrate[(1/z) dtdz, {t, 0, 2 Pi}]

Mathematica graphics

The idea is to convert it to complex contour integration.

z[t_] := Exp[I t];
dt = D[z[t], t]
Integrate[(1/z[t]) dt, {t, 0, 2 Pi}]

Mathematica graphics

Or if you do not want to use functions, use direct expressions:

z = Exp[I t];
dt = D[z, t];
Integrate[(1/z) dt, {t, 0, 2 Pi}]

The idea is to convert it to complex contour integration.

z = Exp[I t];
dz = D[z, t];
Integrate[(1/z) dz, {t, 0, 2 Pi}]

Mathematica graphics

The idea is to convert it to complex contour integration.

Source Link
Nasser
  • 150.6k
  • 12
  • 162
  • 376

z[t_] := Exp[I t];
dt = D[z[t], t]
Integrate[(1/z[t]) dt, {t, 0, 2 Pi}]

Mathematica graphics

Or if you do not want to use functions, use direct expressions:

z = Exp[I t];
dt = D[z, t];
Integrate[(1/z) dt, {t, 0, 2 Pi}]

The idea is to convert it to complex contour integration.