Timeline for Problems with defining a R(c)-linear operator
Current License: CC BY-SA 4.0
4 events
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| Jul 28 at 21:06 | comment | added | Ferca |
Sure!, I edited the code op /: op[f_*expx_] /; FreeQ[expx, c] := f*op[expx], so that the special variable declared is c.
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| Jul 28 at 21:04 | history | edited | Ferca | CC BY-SA 4.0 |
deleted 1 character in body
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| Jul 28 at 18:51 | comment | added | user475525 | Thank you for your answer. It appears that x is declared as a special variable instead of c. Is it possible to go the other way around? | |
| Jul 27 at 8:54 | history | answered | Ferca | CC BY-SA 4.0 |