Timeline for How can I reorder the factors in the terms of a polynomial?
Current License: CC BY-SA 3.0
10 events
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| Aug 10, 2019 at 17:00 | comment | added | Michael E2 |
Actually, I think if the \[MediumSpace] instances are deleted from the def. of polyForm, no substitution rules are needed.
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| Aug 10, 2019 at 16:32 | comment | added | Michael E2 |
@Hotschke This works on the OP's example: RowBox@First@MakeBoxes[#, StandardForm] &@ First@polyForm[ Factor /@ Plus @@@ GatherBy[List @@ poly1, Length@Variables[#] &]] /. "\"\[MediumSpace]-\[MediumSpace]\"" -> "-" // RawBoxes // TeXForm -- Might also need the substitution "\[MediumSpace]+\[MediumSpace]" -> "+", but it doesn't come up in this case.
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| Aug 10, 2019 at 15:34 | comment | added | Hotschke |
polyForm[...]//TeXForm complains withTeXForm::unspt: TeXForm of TemplateSlotSequence[1,] is not supported.. Is it possible to change polyForm so that the output can be given to TeXForm?
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| Aug 11, 2013 at 12:35 | history | edited | Michael E2 | CC BY-SA 3.0 |
Forgot to update the code for polyForm -- family interruptions are another source of error! :)
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| Aug 11, 2013 at 12:13 | history | edited | Michael E2 | CC BY-SA 3.0 |
Corrected code, added example
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| Aug 11, 2013 at 11:38 | comment | added | Mr.Wizard | Oops.. yes, that's what I meant. | |
| Aug 11, 2013 at 11:37 | comment | added | Michael E2 |
@Mr.Wizard Oops, that's right (assuming you mean -3 x1 x3^2) - I blithely thought the point was just to separate the kinds of terms.
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| Aug 11, 2013 at 7:45 | comment | added | Mr.Wizard |
Michael, I don't think this is quite right yet; for example, shouldn't the term −3 x1 x3^3 be the third from the right, not the second as shown above?
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| Aug 11, 2013 at 2:22 | vote | accept | HyperGroups | ||
| Aug 10, 2013 at 22:17 | history | answered | Michael E2 | CC BY-SA 3.0 |