Timeline for Conditioned Probability Task
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Aug 6, 2013 at 7:32 | comment | added | Jens Jensen | Great solution for for 1) However, I still need a solution for 2) | |
| Aug 5, 2013 at 19:49 | comment | added | wolfies |
:) I wasn't correcting you, because what you said is correct. What I was trying to say is that the confusion mostly comes about because mma itself uses the same function name Variance to carry out 2 conceptually very different operations ... and in this instance, for example, it may be unclear as to what one is calculating ... especially given list based input describing the pmf.
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| Aug 5, 2013 at 19:31 | comment | added | ubpdqn | @wolfies thank you for correcting me. Inherent in unbiased , is estimation from sample. My only point was that if you cal the function Variance the calculation will be different in this case. Similarly, use of "PDF for PMF. I guess symbolic overloading is part of making a tractable system. Thank you again for correcting my sloppiness. | |
| Aug 5, 2013 at 14:53 | comment | added | wolfies |
wrote: "Variance uses unbiased estimator and will (appropriately) fail for lists with one element" .......... The real problem is that Mathematica uses the same term Variance to calculate the symbolic calculation of population variance (with regards to a distribution), and the same name to calculate sample variance ... which is something entirely different.
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| Aug 5, 2013 at 9:57 | history | answered | ubpdqn | CC BY-SA 3.0 |