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Feb 10 at 0:12 history bounty ended David G. Stork
Feb 9 at 16:41 vote accept David G. Stork
Feb 6 at 17:55 comment added Domen @azerbajdzan, oh, thanks. I was under the impression that these won't get recalculated every time. Yes, the tooltip just shows the corresponding Fourier component at that particular wavelengths. One could multiply it with the magnitude of the FT, then it would depend on the actual image.
Feb 6 at 17:52 history edited Domen CC BY-SA 4.0
deleted 19 characters in body
Feb 6 at 17:46 comment added azerbajdzan By the way I do not get what the tooltip image should represent since it is totally independent of underlying image? Or maybe the question is more appropriate for OP.
Feb 6 at 17:11 comment added azerbajdzan Putting definitions of dims and imgFT inside first argument of DynamicModule such as: {pos, waves, dims = ImageDimensions[img], imgFT = ImagePeriodogram[img]} increases the speed.
Feb 6 at 16:57 comment added David G. Stork Oh nice... excellent ($+1$). Let me wait just a bit to see if anyone gives a marked improvement, but if not I'll accept, as this nearly suffices, save for speed. (I wouldn't have thought that speed is too much of a problem because one merely needs to read a value and quickly plot a sine wave.)
Feb 6 at 16:10 history answered Domen CC BY-SA 4.0