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Jan 4 at 3:34 vote accept csn899
Jan 2 at 3:03 comment added Bob Hanlon You have a misunderstanding of roots. (-1)^(1/3) // N is complex as is (-1)^(2/3) // N. You presumably want CubeRoot[x] instead of x^(1/3) (look at Reduce[{x^(1/3) == CubeRoot[x], x \[Element] Reals}, x]) and (x^2)^(1/3) instead of x^(2/3) (look at Reduce[{x^(2/3) == (x^2)^(1/3), x \[Element] Reals}, x])
Jan 2 at 0:14 comment added csn899 Thank you very much for providing the code! This is very practical. There are several issues: 1. The function x ^ (1/3) is an odd function, and there are images in the first and third quadrants, but after running the code, there are only images in the first quadrant. 2. The function x ^ (2/3) is an even function, and there are images in both the first and second quadrants, but after running the code, there are only images in the first quadrant.
Jan 1 at 18:13 history answered Bob Hanlon CC BY-SA 4.0