Timeline for RowReduce for symbolic matrices
Current License: CC BY-SA 3.0
11 events
| when toggle format | what | by | license | comment | |
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| Jul 30, 2013 at 14:33 | comment | added | user8774 | To take up your point. I think this might solve the problem, but implementation would be really ugly, because I don't want to solve a linear system. | |
| Jul 29, 2013 at 18:46 | answer | added | David Park | timeline score: 1 | |
| Jul 29, 2013 at 16:06 | history | edited | user8774 | CC BY-SA 3.0 |
added 332 characters in body
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| Jul 29, 2013 at 15:38 | answer | added | trybik | timeline score: 9 | |
| Jul 29, 2013 at 14:48 | answer | added | bill s | timeline score: 2 | |
| Jul 29, 2013 at 14:10 | history | edited | m_goldberg | CC BY-SA 3.0 |
Improved formatting; punctuation; grammar
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| S Jul 29, 2013 at 14:03 | history | suggested | g3kk0 | CC BY-SA 3.0 |
formatting
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| Jul 29, 2013 at 14:02 | review | First posts | |||
| Jul 29, 2013 at 14:10 | |||||
| Jul 29, 2013 at 13:52 | comment | added | Daniel Lichtblau |
Cannot do this directly using RowReduce. But Reduce, as below, can give similar information. Reduce[A.{x, y} == {z, w}] Out[16]= x == z && ((y != 0 && t == w/y) || (y == 0 && w == 0))
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| Jul 29, 2013 at 13:49 | review | Suggested edits | |||
| S Jul 29, 2013 at 14:03 | |||||
| Jul 29, 2013 at 13:44 | history | asked | user8774 | CC BY-SA 3.0 |