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Jul 31, 2023 at 17:31 vote accept korni1990
Jul 31, 2023 at 16:28 answer added Andreas timeline score: 3
Jul 31, 2023 at 13:33 comment added josh The integrand is not real. It's multivalued (like $z^{1/3}$ is). The discontinuity arises from integrating it using a multivalued antiderivative over a path which is not analytically continuous, that is, across its branch point at the origin. Look at ComplexExpand[x^(2/3)/(-x)^(2/3)] and note how the argument of x abruptly changes from $0$ to $\pi$ across the branch point as $x$ changes from negative to positive giving rise to the discontinuity.
Jul 31, 2023 at 12:48 comment added Nasser If differentiating the anti derivative gives back the integrand ($\pm$ constant in anti is OK), then the result is correct, which is in this case. !Mathematica graphics
Jul 31, 2023 at 12:47 comment added Domen Integrate[E^x x^(2/3), {x, 0, x}]
Jul 31, 2023 at 12:44 comment added Ulrich Neumann Your function isn't real for x<0!
Jul 31, 2023 at 12:32 history asked korni1990 CC BY-SA 4.0