Timeline for Partial differentiation with respect to 4 vector
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Jul 5, 2023 at 13:33 | comment | added | Michael E2 |
People here generally like users to post code as copyable Mathematica code as well as images or TeX, so they can copy-paste it. It makes it convenient for them and more likely you will get someone to help you. Judging from the code you tried, you seem to need to spend some time on learning basic syntax. Wolfram.com has resources and there are more here. The underscore does not mean subscript as in TeX and functions require brackets not parentheses: E.g., F(q^2) is F times the (Algebra I) square of q (uses Power[], not Dot[]).
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| S Jul 5, 2023 at 13:20 | history | suggested | Gabriel Picanço | CC BY-SA 4.0 |
Corrected last latex expression, it had a k^2 instead of q^2 in the numerator. It was problematic for whoever tried to check his answer.
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| Jul 5, 2023 at 11:54 | review | Suggested edits | |||
| S Jul 5, 2023 at 13:20 | |||||
| Jul 5, 2023 at 11:46 | answer | added | Gabriel Picanço | timeline score: 1 | |
| Jul 5, 2023 at 8:12 | comment | added | Roland F | As you see from the second line, the expression does not depend on q^2 alone but on q.k too. So d/d^q2 makes no sense. Partial differention, in contrast to its notation, demands to state what are the constants, not what is changing. Becomes more clearly using exterior d. | |
| Jul 5, 2023 at 6:47 | comment | added | Nasser | You seem to be using tensors (from the notation you are using (Covariance and contravariance etc...) , so you need tensor calculus. See how-to-apply-partial-differentiation-w-r-t-tensors as an example using Xact package. There is also mathematica-partial-derivative-with-respect-to-tensors which uses FeynCalc package. | |
| S Jul 5, 2023 at 6:34 | review | First questions | |||
| Jul 5, 2023 at 7:37 | |||||
| S Jul 5, 2023 at 6:34 | history | asked | Tanmoy Pati | CC BY-SA 4.0 |