added 141 characters in body

Source Link

edited Apr 25, 2023 at 4:14

Given the coordinates p1, p2, and p3 of the three vertices of a triangle, find the standard equation for the circumscribed circle of the triangle

ClearAll["`*"]
p1 = {3, 5}
p2 = {6, 7}
p3 = {8, 9}
Cir = CircleThrough[{p1, p2, p3}]
(x - Cir[[1]][[1]])^2 + (y - Cir[[1]][[2]])^2 == (Cir[[-1]])^2

to kglr:

running you code I get the different result：

ClearAll["`*"]
p1 = {3, 5}
p2 = {6, 7}
p3 = {8, 9}
Cir = Insphere[{p1, p2, p3}]
Apply[Total[({x, y} - #)^2] == #2^2 &]@Cir

Given the coordinates p1, p2, and p3 of the three vertices of a triangle, find the standard equation for the circumscribed circle of the triangle

ClearAll["`*"]
p1 = {3, 5}
p2 = {6, 7}
p3 = {8, 9}
Cir = CircleThrough[{p1, p2, p3}]
(x - Cir[[1]][[1]])^2 + (y - Cir[[1]][[2]])^2 == (Cir[[-1]])^2

to kglr:

running you code I get the different result：

Given the coordinates p1, p2, and p3 of the three vertices of a triangle, find the standard equation for the circumscribed circle of the triangle

ClearAll["`*"]
p1 = {3, 5}
p2 = {6, 7}
p3 = {8, 9}
Cir = CircleThrough[{p1, p2, p3}]
(x - Cir[[1]][[1]])^2 + (y - Cir[[1]][[2]])^2 == (Cir[[-1]])^2

to kglr:

running you code I get the different result：

ClearAll["`*"]
p1 = {3, 5}
p2 = {6, 7}
p3 = {8, 9}
Cir = Insphere[{p1, p2, p3}]
Apply[Total[({x, y} - #)^2] == #2^2 &]@Cir

Became Hot Network Question

occurred Apr 24, 2023 at 14:00

added 151 characters in body

Source Link

edited Apr 24, 2023 at 11:25

Given the coordinates p1, p2, and p3 of the three vertices of a triangle, find the standard equation for the circumscribed circle of the triangle

ClearAll["`*"]
p1 = {3, 5}
p2 = {6, 7}
p3 = {8, 9}
Cir = CircleThrough[{p1, p2, p3}]
(x - Cir[[1]][[1]])^2 + (y - Cir[[1]][[2]])^2 == (Cir[[-1]])^2

to kglr:

running you code I get the different result：

Given the coordinates p1, p2, and p3 of the three vertices of a triangle, find the standard equation for the circumscribed circle of the triangle

ClearAll["`*"]
p1 = {3, 5}
p2 = {6, 7}
p3 = {8, 9}
Cir = CircleThrough[{p1, p2, p3}]
(x - Cir[[1]][[1]])^2 + (y - Cir[[1]][[2]])^2 == (Cir[[-1]])^2

Given the coordinates p1, p2, and p3 of the three vertices of a triangle, find the standard equation for the circumscribed circle of the triangle

ClearAll["`*"]
p1 = {3, 5}
p2 = {6, 7}
p3 = {8, 9}
Cir = CircleThrough[{p1, p2, p3}]
(x - Cir[[1]][[1]])^2 + (y - Cir[[1]][[2]])^2 == (Cir[[-1]])^2

to kglr:

running you code I get the different result：

Source Link

asked Apr 24, 2023 at 5:54

Is there a better way to find the equation for finding the coordinates of the three vertices of a known triangle and its circumscribed circle?

Given the coordinates p1, p2, and p3 of the three vertices of a triangle, find the standard equation for the circumscribed circle of the triangle

ClearAll["`*"]
p1 = {3, 5}
p2 = {6, 7}
p3 = {8, 9}
Cir = CircleThrough[{p1, p2, p3}]
(x - Cir[[1]][[1]])^2 + (y - Cir[[1]][[2]])^2 == (Cir[[-1]])^2

ssstriangle

Return to Question