Timeline for Can someone please explain where I am going wrong in the given argument? Is it obvious that $f(m,s)>0$?
Current License: CC BY-SA 4.0
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| Mar 27, 2023 at 15:29 | answer | added | Bob Hanlon | timeline score: 1 | |
| Mar 27, 2023 at 14:54 | comment | added | Domen |
Your reasoning about the minimum is wrong. You cannot simply replace a term with its extremal value, and expect to get the same position (or value) of minima. Imagine a simpler example: $f(x) = x^2 - \sin x$. You cannot reason that $\sin x \in [-1,1] \implies f_{min}(x) = x^2 - 1$. Plot[{x^2 - Sin[x], x^2 - 1}, {x, -2, 2}]
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| Mar 27, 2023 at 14:32 | history | asked | Martha97 | CC BY-SA 4.0 |