Timeline for How to exactly calculate the volume?
Current License: CC BY-SA 4.0
12 events
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| Feb 13, 2023 at 2:53 | history | rollback | J. M.'s missing motivation♦ |
Rollback to Revision 5
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| Feb 12, 2023 at 9:45 | history | edited | user64494 | CC BY-SA 4.0 |
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| Feb 12, 2023 at 9:44 | comment | added | user64494 | @yarchik: I changed my mind after your edit. | |
| Feb 11, 2023 at 19:31 | comment | added | user64494 | I have strong doubts about " but can be evaluated to arbitrary numerical precision. 4.40045471404601150487323349114114025609858633366736911333235058125968\ 8407614606852636185052837712051303716016786758083926093099371567866549\ 2606639295944504935130060271113944852033606388454773344568577". | |
| Feb 11, 2023 at 7:36 | history | edited | yarchik | CC BY-SA 4.0 |
Response added
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| Feb 10, 2023 at 17:17 | comment | added | kirma |
Heh, clearly I didn't pay much attention as I only now noticed that you have used CylindricalDecomposition in association with numeric integration... yes, it comes handy on these sort of problems in various forms. :)
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| Feb 10, 2023 at 8:47 | comment | added | user64494 |
+1. Thank you. You wrote "The final result can also be reduced to 1D integral...". Can you kindly present that integral in your answer? TIA. What does CylindrigalDecomposition do?
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| Feb 9, 2023 at 22:42 | comment | added | Bob Hanlon |
Using ResourceFunction["RadicalDenest"] the expression can be simplified to (-(4/3))*(-2 - 10*Sqrt[2] + 6*Sqrt[3] + Sqrt[6])
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| Feb 9, 2023 at 21:16 | history | edited | yarchik | CC BY-SA 4.0 |
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| Feb 9, 2023 at 21:10 | history | edited | yarchik | CC BY-SA 4.0 |
added 177 characters in body
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| Feb 9, 2023 at 21:04 | history | edited | yarchik | CC BY-SA 4.0 |
added 177 characters in body
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| Feb 9, 2023 at 20:43 | history | answered | yarchik | CC BY-SA 4.0 |