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user64494
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I think CASes apply a usual method of solving linear recurrence relations with constant coefficients (for example, see Wiki for info). In any case the result of the command of Maple

infolevel[all] := 4: rsolve(a(n+1) = k*a(n)+b, a(n));

confirms that guess.

Addition. As step-by-step solution by W|A shows, the generating function is used to this end there.

Addition 2. See here and here and here.

I think CASes apply a usual method of solving linear recurrence relations with constant coefficients (for example, see Wiki for info). In any case the result of the command of Maple

infolevel[all] := 4: rsolve(a(n+1) = k*a(n)+b, a(n));

confirms that guess.

Addition. As step-by-step solution by W|A shows, the generating function is used to this end there.

I think CASes apply a usual method of solving linear recurrence relations with constant coefficients (for example, see Wiki for info). In any case the result of the command of Maple

infolevel[all] := 4: rsolve(a(n+1) = k*a(n)+b, a(n));

confirms that guess.

Addition. As step-by-step solution by W|A shows, the generating function is used to this end there.

Addition 2. See here and here and here.

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user64494
  • 29.1k
  • 4
  • 29
  • 56

I think CASes apply a usual method of solving linear recurrence relations with constant coefficients (for example, see Wiki for info). In any case the result of the command of Maple

infolevel[all] := 4: rsolve(a(n+1) = k*a(n)+b, a(n));

confirms that guess.

Addition. As step-by-step solution by W|A shows, the generating function is used to this end there.

I think CASes apply a usual method of solving linear recurrence relations with constant coefficients (for example, see Wiki for info). In any case the result of the command of Maple

infolevel[all] := 4: rsolve(a(n+1) = k*a(n)+b, a(n));

confirms that guess.

I think CASes apply a usual method of solving linear recurrence relations with constant coefficients (for example, see Wiki for info). In any case the result of the command of Maple

infolevel[all] := 4: rsolve(a(n+1) = k*a(n)+b, a(n));

confirms that guess.

Addition. As step-by-step solution by W|A shows, the generating function is used to this end there.

Source Link
user64494
  • 29.1k
  • 4
  • 29
  • 56

I think CASes apply a usual method of solving linear recurrence relations with constant coefficients (for example, see Wiki for info). In any case the result of the command of Maple

infolevel[all] := 4: rsolve(a(n+1) = k*a(n)+b, a(n));

confirms that guess.