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Aug 31, 2022 at 10:36 vote accept MOOSE
Aug 30, 2022 at 7:21 comment added MOOSE Thanks for the answer. This also seems like a natural way to do it. Initially, I was hesitant to define it this way because in the solution for the upper and lower limit the term $\log\left(\frac{p}{1-p}\right)$ shows up which diverges as $p$ approaches either $1$ or $0$. It seems to cause difficulty if we're interested in e.g ED90 instead of ED50. Do you have a comment for this limit? I'm not trying to be picky on your answer or anything, just trying to understand whats going on.
Aug 29, 2022 at 19:56 comment added JimB And depending on the data, one can get $-\infty$ and/or $+\infty$ for the confidence limits.
Aug 29, 2022 at 19:55 history edited JimB CC BY-SA 4.0
Changed "they" to "the".
Aug 29, 2022 at 15:42 history answered JimB CC BY-SA 4.0