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Aug 11, 2022 at 9:42 comment added seeker I invite you to my new question mathematica.stackexchange.com/questions/271948/…
Aug 11, 2022 at 8:59 comment added seeker The inequality $|x\pm y| \le |1\pm z|$ actually leads to four inequalities $z \ge x+y-1; ~z\le -x+y+1;~z\le x-y+1;~z \ge -x-y-1.$
Aug 11, 2022 at 8:45 comment added seeker Thanks @H. Zhou, but Rom38's approach (with due respect to his expertise) seems hard to me. Could you incorporate this in your answer?
Aug 11, 2022 at 7:35 comment added H. Zhou @seeker For this one I would use Select, in a similar way as that suggested by @Rom38.
Aug 10, 2022 at 19:08 comment added seeker Thanks, @H. Zhou, that works! However, I have a final constraint $|x \pm y| \le |1 \pm z|$ arising due to some physical reasons. How can I take this into account? Should I ask it as a new question?
Aug 9, 2022 at 9:11 comment added H. Zhou @seeker If you mean a linear relation between a_i's then I think you can first generate random numbers for a_{1,2,3,4}, then compute a5=1-a1-a2-a3-a4.
Aug 9, 2022 at 8:58 comment added seeker Thanks @H. Zhou. I have a similar situation where now in place of $a$, there is a set $a_1,a_2,a_3,a_4,a_5$ and they are real and also constrained to $\sum_{i=1}^{5} a_i = 1$. How to handle this situation?
Aug 8, 2022 at 20:04 vote accept seeker
S Aug 8, 2022 at 8:16 review First answers
Aug 8, 2022 at 16:35
S Aug 8, 2022 at 8:16 history answered H. Zhou CC BY-SA 4.0