Skip to main content
added 1 character in body
Source Link
Akku14
  • 17.4k
  • 15
  • 32

Since x and y are form 0 to Pi/2, eliminating Cos and converingconverting Sin[x] == sx, Sin[y] == sy.

Since x and y are form 0 to Pi/2, eliminating Cos and convering Sin[x] == sx, Sin[y] == sy.

Since x and y are form 0 to Pi/2, eliminating Cos and converting Sin[x] == sx, Sin[y] == sy.

added 1599 characters in body
Source Link
Akku14
  • 17.4k
  • 15
  • 32

Edit

Solution with Maximize.

Maximize works best with linear and polynomial expressions.( See help function) Therefore using variable transformations.

an = x^n - x^(2 n) // Factor

(*   -x^n (-1 + x^n)   *)

max = Maximize[{an /. x^n -> xn, 0 <= xn <= 1}, xn]

(*   {1/4, {xn -> 1/2}}   *)

Solve[(xn /. max[[2]]) == x^n && 0 <= x <= 1 && n > 0, x]

(*   {{x -> ConditionalExpression[2^(-1/n), n > 0]}}   *)

A solution with Reduce

Didn't get Maximize to extract max of an from red.

Example from comment.

Since x and y are form 0 to Pi/2, eliminating Cos and convering Sin[x] == sx, Sin[y] == sy.

anequ = an==n(Sin[x] + Cos[y] + Cos[x - y])//TrigExpand

(*   (0 <= x <= \[Pi]/2, 0 <= y <= \[Pi]/2)    *)

eli = Eliminate[{anequ, Sin[x]^2 + Cos[x]^2 == 1, 
   Sin[y]^2 + Cos[y]^2 == 1, Sin[x] == sx, Sin[y] == sy}, {Cos[x], 
   Cos[y]}]

sol1 = First@
   Solve[{Sin[x] == sx, Sin[y] == sy, 0 <= x <= Pi/2, 
     0 <= y <= Pi/2}, {x, y}] // 
  Simplify[#, {0 <= x <= Pi/2, 0 <= y <= Pi/2}] &

eli2 = List @@ (eli /. sol1 // Simplify)

(*   {an^4 + 4 n^4 sx^2 (1 + sy)^2 (-1 + sx^2 + sy^2) + 
   4 an^2 n^2 (1 + sy) (-1 + sy + sx^2 (2 + sy)) == 
  4 an n sx (1 + sy) (an^2 + 2 n^2 (1 + sy) (-1 + sx^2 + sy)), 
 0 <= sy < 1 && 0 <= sx < 1}   *)

max = Maximize[{an, eli2 && n > 0}, {an, sx, sy}] // 
  Simplify[#, Assumptions -> Element[n, Integers] && n > 0] &

(*   {(3 Sqrt[3] n)/2, {an -> (3 Sqrt[3] n)/2, sx -> Sqrt[3]/2, sy -> 1/2}}   *)

{x -> ArcSin[sx], y -> ArcSin[sy]} /. max[[2]]

(*   {x -> Pi/3, y -> Pi/6}   *)

A solution with Reduce

Didn't get Maximize to extract max of an from red.

Edit

Solution with Maximize.

Maximize works best with linear and polynomial expressions.( See help function) Therefore using variable transformations.

an = x^n - x^(2 n) // Factor

(*   -x^n (-1 + x^n)   *)

max = Maximize[{an /. x^n -> xn, 0 <= xn <= 1}, xn]

(*   {1/4, {xn -> 1/2}}   *)

Solve[(xn /. max[[2]]) == x^n && 0 <= x <= 1 && n > 0, x]

(*   {{x -> ConditionalExpression[2^(-1/n), n > 0]}}   *)

A solution with Reduce

Didn't get Maximize to extract max of an from red.

Example from comment.

Since x and y are form 0 to Pi/2, eliminating Cos and convering Sin[x] == sx, Sin[y] == sy.

anequ = an==n(Sin[x] + Cos[y] + Cos[x - y])//TrigExpand

(*   (0 <= x <= \[Pi]/2, 0 <= y <= \[Pi]/2)    *)

eli = Eliminate[{anequ, Sin[x]^2 + Cos[x]^2 == 1, 
   Sin[y]^2 + Cos[y]^2 == 1, Sin[x] == sx, Sin[y] == sy}, {Cos[x], 
   Cos[y]}]

sol1 = First@
   Solve[{Sin[x] == sx, Sin[y] == sy, 0 <= x <= Pi/2, 
     0 <= y <= Pi/2}, {x, y}] // 
  Simplify[#, {0 <= x <= Pi/2, 0 <= y <= Pi/2}] &

eli2 = List @@ (eli /. sol1 // Simplify)

(*   {an^4 + 4 n^4 sx^2 (1 + sy)^2 (-1 + sx^2 + sy^2) + 
   4 an^2 n^2 (1 + sy) (-1 + sy + sx^2 (2 + sy)) == 
  4 an n sx (1 + sy) (an^2 + 2 n^2 (1 + sy) (-1 + sx^2 + sy)), 
 0 <= sy < 1 && 0 <= sx < 1}   *)

max = Maximize[{an, eli2 && n > 0}, {an, sx, sy}] // 
  Simplify[#, Assumptions -> Element[n, Integers] && n > 0] &

(*   {(3 Sqrt[3] n)/2, {an -> (3 Sqrt[3] n)/2, sx -> Sqrt[3]/2, sy -> 1/2}}   *)

{x -> ArcSin[sx], y -> ArcSin[sy]} /. max[[2]]

(*   {x -> Pi/3, y -> Pi/6}   *)
Source Link
Akku14
  • 17.4k
  • 15
  • 32

A solution with Reduce

(red = List @@ 
    Reduce[{an == x^n - x^(2 n), 0 <= x <= 1, n > 0, 
      Element[n, Integers]}, x, Reals, 
     Backsubstitution -> True]) // TableForm

enter image description here

Maximum for an is 1/4 at x == 2^(-1/n).

Didn't get Maximize to extract max of an from red.