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Jul 4, 2022 at 15:23 vote accept hana
Jul 4, 2022 at 8:38 history edited J. M.'s missing motivation CC BY-SA 4.0
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Jul 3, 2022 at 17:20 comment added J. M.'s missing motivation Formally: Composition[Function[x, 6 x - 2], InverseFunction[Function[x, x + 6]]][x]
Jul 3, 2022 at 8:25 history became hot network question
Jul 3, 2022 at 6:00 history tweeted twitter.com/StackMma/status/1543474635500666880
Jul 3, 2022 at 1:42 history edited Michael E2
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Jul 3, 2022 at 0:54 history edited hana CC BY-SA 4.0
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Jul 3, 2022 at 0:46 answer added Michael E2 timeline score: 13
Jul 3, 2022 at 0:32 history edited hana CC BY-SA 4.0
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Jul 3, 2022 at 0:32 comment added thorimur Unfortunately I think mathematica can't solve for functions per se...however, you could possibly try to use InverseFunction in some way to express $h \circ f^{-1}$, or do something clever by somehow turning this into a differential equation for g. That would be cool. Of course both of these approaches have restrictions, and I'd be happy to see a more general approach.
Jul 3, 2022 at 0:21 history asked hana CC BY-SA 4.0