Timeline for Behavior of Mathematica 12.3.1, 13.0.1 under certain integrations
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 2, 2022 at 7:01 | comment | added | BabaYaga |
I agree that your integral is divergent. This can be also seen by just expanding your result around a=0. My question: whether a series expansion is permissible on both sides. If yes, then it would be an infinite sum of finite terms/integrals. One of which would be the integrand in the question. In some way, the divergence will be regulated with 1/a kind of term.
|
|
| Jul 2, 2022 at 6:47 | comment | added | BabaYaga | Btw I see that you have started with a different integration and then taking a->0. | |
| Jul 2, 2022 at 6:31 | comment | added | BabaYaga | Then the question is after your comparison plot if one can compare coefficients of ‘a’ which is finite and corresponds to the original integral. | |
| Jul 1, 2022 at 22:24 | history | answered | Andreas | CC BY-SA 4.0 |