Timeline for Solve singular fourth order ODE
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
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| Jul 20, 2022 at 9:00 | history | tweeted | twitter.com/StackMma/status/1549680530156883968 | ||
| Jun 17, 2022 at 4:08 | answer | added | user293787 | timeline score: 7 | |
| Jun 16, 2022 at 21:22 | comment | added | Charlie | @MichaelSeifert Sorry I meant to say I want to neglect the terms that weren't $\mathcal{O}(1/r7)$ | |
| Jun 16, 2022 at 18:44 | answer | added | Michael Seifert | timeline score: 7 | |
| Jun 16, 2022 at 17:20 | comment | added | Michael Seifert | It doesn't make a lot of sense to neglect the terms that are dominant as $r \to 0$ (since $r^{-6} \gg r^{-3}$, $r^{-5} \gg r^{-2}$, etc. as $r \to 0$.) | |
| Jun 16, 2022 at 15:36 | history | edited | Charlie | CC BY-SA 4.0 |
added 611 characters in body
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| Jun 16, 2022 at 15:21 | comment | added | Charlie | @user293787 The biharmonic has four solutions, are you saying I should do some perturbation but that would break down at the origin. | |
| Jun 16, 2022 at 15:16 | comment | added | Charlie | i is imaginary i. The four boundary conditions would be value of $\psi$ at the boundary and at the origin $\psi$ and all derivatives are zero. | |
| Jun 16, 2022 at 13:17 | comment | added | user293787 |
To get started, you may want to look at the homogeneousPart[f_]:=-3/r^4*f+3/r^3*D[f,r]-3/r^2*D[f,{r,2}]+2/r*D[f,{r,3}]+D[f,{r,4}] and check that it has the four solutions Map[homogeneousPart,{1/r,r,r*Log[r],r^3}]//Simplify. Btw, please provide Mathematica expressions.
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| Jun 16, 2022 at 10:20 | comment | added | Mariusz Iwaniuk |
NDSolve needs four boundary(initial) condition? What is: i in: 300 i a parameter?
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| Jun 16, 2022 at 8:58 | history | asked | Charlie | CC BY-SA 4.0 |