Timeline for How to take the derivative with respect to a function with more than one variable?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| S Jun 7, 2022 at 11:43 | vote | accept | Victor Nielsen | ||
| Jun 7, 2022 at 11:43 | vote | accept | Victor Nielsen | ||
| S Jun 7, 2022 at 11:43 | |||||
| Jun 3, 2022 at 15:18 | comment | added | Alan | I created an answer to show what I mean in more detail. | |
| Jun 2, 2022 at 21:35 | answer | added | Alan | timeline score: 1 | |
| Jun 2, 2022 at 21:12 | comment | added | Alan |
After you substitute for p[x,params] you also need to substitute forparams; this will produce an express in x.
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| Jun 2, 2022 at 14:40 | comment | added | Victor Nielsen | @Alan When I do that, I get an equation rather than a number. I would like to see if the result is positive or negative. | |
| Jun 1, 2022 at 13:55 | answer | added | Daniel Huber | timeline score: 1 | |
| Jun 1, 2022 at 13:35 | comment | added | Alan |
So you are trying to compute D[(1 - \[Gamma])^(\[Gamma]/(1 - \[Gamma]))*E^\[Omega]*p^(\[Epsilon] + 1)*((E^\[Omega]*p )), p]? If so, you can do that and then substitute for p.
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| Jun 1, 2022 at 13:18 | history | asked | Victor Nielsen | CC BY-SA 4.0 |