Timeline for Hard Integral with Numerical Approximation
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Jan 29, 2022 at 5:55 | vote | accept | WhimsicalWish | ||
| Jan 28, 2022 at 16:42 | answer | added | ConservedCharge | timeline score: 0 | |
| Jan 28, 2022 at 8:09 | comment | added | Nasser |
It has nothing to do with x. The integral Integrate[(Tanh[Y]^2)*(Y)^(1/6), Y] does not evaluate analytically. Need to use Numerical integration as shown above.
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| Jan 28, 2022 at 8:03 | history | edited | WhimsicalWish | CC BY-SA 4.0 |
changed xFunction to xFunction[x]
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| Jan 28, 2022 at 6:19 | comment | added | Michael E2 |
Do you mean (xFunction[x] - Y) in the integrand and not (xFunction - Y)?
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| Jan 28, 2022 at 6:09 | history | edited | WhimsicalWish | CC BY-SA 4.0 |
Defined CFunction, improved explanation, changed polynomial to rational
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| Jan 28, 2022 at 4:25 | comment | added | ConservedCharge |
It is good practice to avoid using single capital letters as variable names in Mathematica (in particular, avoid C, since it has special meaning in Wolfram Language). Changing C to c and defining a test polynomial CFunction[x_] := 3 x^2 - 5 x^3, I do get a numerical result: With[{c = 0.6}, NIntegrate[(Tanh[Y]^2)*(CFunction[Y] - Y)^(1/6), {Y, .3, c}]]
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| Jan 28, 2022 at 3:09 | comment | added | MarcoB | Please include the full definition of Cfunction and C. | |
| S Jan 28, 2022 at 2:53 | review | First questions | |||
| Jan 28, 2022 at 5:10 | |||||
| S Jan 28, 2022 at 2:53 | history | asked | WhimsicalWish | CC BY-SA 4.0 |