I would like to generate a 3D matrix like the 3D figure below.
How to generate a tubular shell branching process in 3D like that image? (veins dynamic from cellular automata?)
n=128; (*dimension of matrix*)
f[i_,j_,k_]:= (*rule to generate the branches tube*)
s = SparseArray[{{i_, j_,k_} -> f[i, j, k]}, {n, n, n}]; (*matrix*)
t = Tube[{s}, {0.6, 0.4}]; (*tube*)
Could anybody help me to obtain the matrix, please?
I would like to generate a 3D matrix like the 3D figure below.
How to generate a tubular shell branching process in 3D like that image? (veins dynamic from cellular automata?)
n=128; (*dimension of matrix*)
f[i_,j_,k_]:= (*rule to generate the branches tube*)
s = SparseArray[{{i_, j_,k_} -> f[i, j, k]}, {n, n, n}]; (*matrix*)
t = Tube[{s}, {0.6, 0.4}]; (*tube*)
Could anybody help me to obtain the matrix, please?
I would like to generate a 3D matrix like the 3D figure below.
How to generate a tubular shell branching process in 3D like that image? (veins dynamic from cellular automata?)
n=128; (*dimension of matrix*)
f[i_,j_,k_]:= (*rule to generate the branches tube*)
s = SparseArray[{{i_, j_,k_} -> f[i, j, k]}, {n, n, n}]; (*matrix*)
t = Tube[{s}, {0.6, 0.4}]; (*tube*)
Could anybody help me to obtain the matrix, please?
As a follow up of this question and that answer, I would like to generate a 3D matrix from a 3D figure, like the image3D figure below.
How to generate a tubular shell branching process in 3D like that image? (veins dynamic from cellular automata?)
n=128; (*dimension of matrix*)
f[i_,j_,k_]:= (*rule to generate the branches tube*)
s = SparseArray[{{i_, j_,k_} -> f[i, j, k]}, {n, n, n}]; (*matrix*)
t = Tube[{s}, {0.6, 0.4}]; (*tube*)
Could anybody help me to obtain the matrix, please?
As a follow up of this question and that answer, I would like to generate a 3D matrix from a 3D figure, like the image below.
How to generate a tubular shell branching process in 3D like that image? (veins dynamic from cellular automata?)
n=128; (*dimension of matrix*)
f[i_,j_,k_]:= (*rule to generate the branches tube*)
s = SparseArray[{{i_, j_,k_} -> f[i, j, k]}, {n, n, n}]; (*matrix*)
t = Tube[{s}, {0.6, 0.4}]; (*tube*)
Could anybody help me to obtain the matrix, please?
I would like to generate a 3D matrix like the 3D figure below.
How to generate a tubular shell branching process in 3D like that image? (veins dynamic from cellular automata?)
n=128; (*dimension of matrix*)
f[i_,j_,k_]:= (*rule to generate the branches tube*)
s = SparseArray[{{i_, j_,k_} -> f[i, j, k]}, {n, n, n}]; (*matrix*)
t = Tube[{s}, {0.6, 0.4}]; (*tube*)
Could anybody help me to obtain the matrix, please?
As a follow up of this question and that answer, I would like to generate a 3D matrix from a 3D figure, like the image below.
However, although the image depicts a 3D plot, there are only 2D (429x399) pixels. I'm trying to get a 3D matrix (128x128x128) of 1's and 0's where the 0's represent the branches' pixels and the transparent part are 1's inside of the box. The code used by me was
img = Import["C:\\Users\\Usuario\\Desktop\\image.png", "Image3D"];
ImageDimensions[img];
n = 128;
image = ImageResize[img, {n, n, n}];
data = ImageData[MorphologicalBinarize[image]];
But, img imported don't be in 3D. Can depth be calculated from a single 2d picture? (or unless there are cues such as color)?
If it is can't get a 3D image from 2D (and hence a 3D matrix), howHow to generate a tubular shell branching process in 3D like that image? (veins dynamic from cellular automata?)
n=128; (*dimension of matrix*)
f[i_,j_,k_]:= (*rule to generate the branches tube*)
s = SparseArray[{{i_, j_,k_} -> f[i, j, k]}, {n, n, n}]; (*matrix*)
t = Tube[{s}, {0.6, 0.4}]; (*tube*)
Could anybody help me to obtain the matrix, please?
As a follow up of this question and that answer, I would like to generate a 3D matrix from a 3D figure, like the image below.
However, although the image depicts a 3D plot, there are only 2D (429x399) pixels. I'm trying to get a 3D matrix (128x128x128) of 1's and 0's where the 0's represent the branches' pixels and the transparent part are 1's inside of the box. The code used by me was
img = Import["C:\\Users\\Usuario\\Desktop\\image.png", "Image3D"];
ImageDimensions[img];
n = 128;
image = ImageResize[img, {n, n, n}];
data = ImageData[MorphologicalBinarize[image]];
But, img imported don't be in 3D. Can depth be calculated from a single 2d picture? (or unless there are cues such as color)?
If it is can't get a 3D image from 2D (and hence a 3D matrix), how to generate a tubular shell branching process like that image?
n=128; (*dimension of matrix*)
f[i_,j_,k_]:= (*rule to generate the branches tube*)
s = SparseArray[{{i_, j_,k_} -> f[i, j, k]}, {n, n, n}]; (*matrix*)
t = Tube[{s}, {0.6, 0.4}]; (*tube*)
Could anybody help me to obtain the matrix, please?
As a follow up of this question and that answer, I would like to generate a 3D matrix from a 3D figure, like the image below.
How to generate a tubular shell branching process in 3D like that image? (veins dynamic from cellular automata?)
n=128; (*dimension of matrix*)
f[i_,j_,k_]:= (*rule to generate the branches tube*)
s = SparseArray[{{i_, j_,k_} -> f[i, j, k]}, {n, n, n}]; (*matrix*)
t = Tube[{s}, {0.6, 0.4}]; (*tube*)
Could anybody help me to obtain the matrix, please?