Timeline for How does Leafcount work? [closed]
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Nov 24, 2021 at 5:23 | history | closed |
Michael E2 bbgodfrey MarcoB Rohit Namjoshi Dunlop |
Not suitable for this site | |
| Nov 24, 2021 at 1:16 | vote | accept | Peter Burbery | ||
| Nov 23, 2021 at 20:02 | answer | added | Ian Ford | timeline score: 3 | |
| Nov 23, 2021 at 4:51 | review | Close votes | |||
| Nov 24, 2021 at 5:23 | |||||
| Nov 22, 2021 at 22:19 | comment | added | Peter Burbery | Thank you it worked! | |
| Nov 22, 2021 at 22:17 | comment | added | Domen |
Take a look at ExpressionTree[ThreeFive ...] and ExpressionTree[Floor[n/15]]. You can see that your definition of function gets evaluated (!) and returns "nothing" (or something like this, I am not sure), therefore only one leaf. Try with Hold: LeafCount[Hold[ThreeFive[...] := ...]], which will give you 17 leafs (one of them being Hold itself).
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| Nov 22, 2021 at 21:43 | history | asked | Peter Burbery | CC BY-SA 4.0 |