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May 30, 2022 at 14:35 comment added Vaclav Kotesovec I added a new sequence to the OEIS, see oeis.org/A354450. To calculate the more accurate value of this sum, it was more appropriate to use Maple instead of Mathematica. Series[(1 - Log[n]/n)^(2*n), {n, Infinity, 30}] is for many hours. In Maple, the expansion of 100 terms is done almost immediately.
Dec 7, 2021 at 11:15 comment added Rom38 You can just plot the sum-terms with increasing n and see that the curve goes to zero.
Dec 6, 2021 at 13:25 answer added Greg Hurst timeline score: 5
Nov 30, 2021 at 13:55 answer added Валерий Заподовников timeline score: 6
Nov 2, 2021 at 13:59 history became hot network question
Nov 2, 2021 at 12:00 history tweeted twitter.com/StackMma/status/1455504993168072707
Nov 2, 2021 at 11:56 vote accept user64494
Nov 2, 2021 at 11:55 vote accept user64494
Nov 2, 2021 at 11:55
Nov 2, 2021 at 8:55 comment added user64494 The option Method->"IntegralTest" should correctly work here in view of AsymptoticEqual[(1 - Log[n]/n)^(2 n), 1/n^2, n -> Infinity] which answers True, but fails.
Nov 2, 2021 at 8:40 answer added Daniel Huber timeline score: 8
Nov 2, 2021 at 8:23 history edited user64494
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Nov 2, 2021 at 8:12 answer added Mauricio Fernández timeline score: 2
Nov 2, 2021 at 5:57 history asked user64494 CC BY-SA 4.0