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Nov 2, 2021 at 9:00 history tweeted twitter.com/StackMma/status/1455459675491733511
Nov 1, 2021 at 19:57 vote accept user46831
Nov 1, 2021 at 19:53 comment added user46831 Thanks Nasser, sadly this proves complicated too because x here is a function of y and I just want the partial evaluated at x[y] not the partial of func[x[y],i,y]. I could get around that with D[func[x,2,y],y]/.x->x[y], but the expressions are complicated and I hope to avoid all that. Hence my use of Derivative. Much appreciated though.
Nov 1, 2021 at 1:56 history became hot network question
Oct 31, 2021 at 18:45 answer added Michael E2 timeline score: 5
Oct 31, 2021 at 18:12 comment added Nasser Try D[func[x, 2, y], y] which gives 2 + z[2]'[y]
Oct 31, 2021 at 17:55 history asked user46831 CC BY-SA 4.0