For a given list, say {94,35,47,29,86,40,46,72,87}, how can I have a list of even and odd numbers.

GroupBy[{94,35,47,29,86,40,46,72,87,84,49,82,100,99,7,70,67,63,13,91,18,94,94,15,72,39,4,7,31,67,65,37,93,9,4,84,97,60,48,61,91,24,10,46,42,28,41,36,62,70,78,38,80,70,63,20,21,7,54,26,17,73,100,56,36,54,100,46,0,59,77,80,57,82,63,74,8,47,68,74,54,57,4,90,14,31,88,23,30,37,95,44,100,12,23,48,4,14,100,57},EvenQ] 

True->{94,86,40,46,72,84,82,100,70,18,94,94,72,4,4,84,60,48,24,10,46,42,28,36,62,70,78,38,80,70,20,54,26,100,56,36,54,100,46,0,80,82,74,8,68,74,54,4,90,14,88,30,44,100,12,48,4,14,100},False->{35,47,29,87,49,99,7,67,63,13,91,15,39,7,31,67,65,37,93,9,97,61,91,41,63,21,7,17,73,59,77,57,63,47,57,31,23,37,95,23,57}\

What is needed is the count.True->54,False->49.

With CountsBy as suggested by @sjoerd-smit, I get the count of even and odd numbers in one command. CountsBy[{94,35,47,29,86,40,46,72,87,84,49,82,100,99,7,70,67,63,13,91,18,94,94,15,72,39,4,7,31,67,65,37,93,9,4,84,97,60,48,61,91,24,10,46,42,28,41,36,62,70,78,38,80,70,63,20,21,7,54,26,17,73,100,56,36,54,100,46,0,59,77,80,57,82,63,74,8,47,68,74,54,57,4,90,14,31,88,23,30,37,95,44,100,12,23,48,4,14,100,57},EvenQ]

Input: Median[{35,47,29,87,49,99,7,67,63,13,91,15,39,7,31,67,65,37,93,9,97,61,91,41,63,21,7,17,73,59,77,57,63,47,57,31,23,37,95,23,57}]

For a given list, say {94,35,47,29,86,40,46,72,87}, how can I find a list of even and odd numbers.

GroupBy[{94,35,47,29,86,40,46,72,87,84,49,82,100,99,7,70,67,63,13,
  91,18,94,94,15,72,39,4,7,31,67,65,37,93,9,4,84,97,60,48,61,91,24,10,
  46,42,28,41,36,62,70,78,38,80,70,63,20,21,7,54,26,17,73,100,56,36,
  54,100,46,0,59,77,80,57,82,63,74,8,47,68,74,54,57,4,90,14,31,88,23,
  30,37,95,44,100,12,23,48,4,14,100,57},EvenQ] 

True->  {94,86,40,46,72,84,82,100,70,18,94,94,72,4,4,84,60,48,24,10,46,
  42,28,36,62,70,78,38,80,70,20,54,26,100,56,36,54,100,46,0,80,
  82,74,8,68,74,54,4,90,14,88,30,44,100,12,48,4,14,100}, 
False->  {35,47,29,87,49,99,7,67,63,13,91,15,39,7,31,67,65,37,93,9,97,
  61,91,41,63,21,7,17,73,59,77,57,63,47,57,31,23,37,95,23,57}

What is needed is the count. True->54, False->49.

With CountsBy as suggested by @sjoerd-smit, I get the count of even and odd numbers in one command.

CountsBy[{94,35,47,29,86,40,46,72,87,84,49,82,100,99,7,70,67,63,13,
  91,18,94,94,15,72,39,4,7,31,67,65,37,93,9,4,84,97,60,48,61,91,24,10,
  46,42,28,41,36,62,70,78,38,80,70,63,20,21,7,54,26,17,73,100,56,36,
  54,100,46,0,59,77,80,57,82,63,74,8,47,68,74,54,57,4,90,14,31,88,23,
  30,37,95,44,100,12,23,48,4,14,100,57},EvenQ]

Input:

Median[{35,47,29,87,49,99,7,67,63,13,91,15,39,7,31,67,65,37,93,
9,97,61,91,41,63,21,7,17,73,59,77,57,63,47,57,31,23,37,95,23,57}] 

With CountsBy as suggested by @sjoerd-smit, I get the count of even and odd numbers in one command. CountsBy[{94,35,47,29,86,40,46,72,87,84,49,82,100,99,7,70,67,63,13,91,18,94,94,15,72,39,4,7,31,67,65,37,93,9,4,84,97,60,48,61,91,24,10,46,42,28,41,36,62,70,78,38,80,70,63,20,21,7,54,26,17,73,100,56,36,54,100,46,0,59,77,80,57,82,63,74,8,47,68,74,54,57,4,90,14,31,88,23,30,37,95,44,100,12,23,48,4,14,100,57},EvenQ]

By Median applied individually, I could get the medians of even and odd numbers in the list.

Input: Median[{35,47,29,87,49,99,7,67,63,13,91,15,39,7,31,67,65,37,93,9,97,61,91,41,63,21,7,17,73,59,77,57,63,47,57,31,23,37,95,23,57}]

Output: 49

Similarly, for the list of even numbers.

Might be a way to get the same with one command.

For a given list, say {94,35,47,29,86,40,46,72,87}, how can I have a list of even and odd numbers.

Here is the output after trying with the suggested solution in the answer.

After putting the number in list as told by @Nasser, I got the intended output.

For a given list, say {94,35,47,29,86,40,46,72,87}, how can I have a list of even and odd numbers.

Here is the output after trying with the suggested solution in the answer.

After putting the number in list as told by @Nasser, I got the intended output.

I am seeking to solve this problem:

Create an Association that lists the Median of the even and odd numbers respectively under the keys True and False. (Hint: Use GroupBy with EvenQ.)

By applying GroupBy, I could now list the even and odd numbers:

Input:

GroupBy[{94,35,47,29,86,40,46,72,87,84,49,82,100,99,7,70,67,63,13,91,18,94,94,15,72,39,4,7,31,67,65,37,93,9,4,84,97,60,48,61,91,24,10,46,42,28,41,36,62,70,78,38,80,70,63,20,21,7,54,26,17,73,100,56,36,54,100,46,0,59,77,80,57,82,63,74,8,47,68,74,54,57,4,90,14,31,88,23,30,37,95,44,100,12,23,48,4,14,100,57},EvenQ] 

Output:

True->{94,86,40,46,72,84,82,100,70,18,94,94,72,4,4,84,60,48,24,10,46,42,28,36,62,70,78,38,80,70,20,54,26,100,56,36,54,100,46,0,80,82,74,8,68,74,54,4,90,14,88,30,44,100,12,48,4,14,100},False->{35,47,29,87,49,99,7,67,63,13,91,15,39,7,31,67,65,37,93,9,97,61,91,41,63,21,7,17,73,59,77,57,63,47,57,31,23,37,95,23,57}\

What is needed is the count.True->54,False->49.