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Jan 28, 2017 at 23:45 answer added Michael E2 timeline score: 3
May 22, 2013 at 1:02 comment added Fred Daniel Kline +1 for the plot of the "Loch Ness" monster.
May 18, 2013 at 14:57 history edited lagoa CC BY-SA 3.0
the previous plot was too rough
May 17, 2013 at 14:28 comment added lagoa I get a negligible better time ( 0.1 secs difference) if the integration method is the LevinRule.
May 17, 2013 at 14:07 comment added gpap Have you seen the relevant section for "LevinRule" ? It seems to be spot on for oscillatory integrals with small oscillation around a kernel.
May 17, 2013 at 12:19 comment added lagoa They are important numerical values. I have edited the question with their values. Thanks for pointing it out.
May 17, 2013 at 12:19 history edited lagoa CC BY-SA 3.0
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May 17, 2013 at 2:26 history edited Mr.Wizard
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May 17, 2013 at 2:24 comment added Michael E2 What are k, ks and \[Delta]pz? For instance, this takes less than a second to evaluate: NIntegrate[2 Sqrt[\[Pi]] E^(-x^2/2) E^(-(x - X)^2/2) r/Sqrt[(x - x0)^2 + r^2] E^(-ks Sqrt[r^2 + (x - x0)^2]) BesselJ[0, Sqrt[(X + 2*k)^2 + \[Delta]pz^2] r] /. {k -> 1, ks -> 1, \[Delta]pz -> 1, x0 -> 0, X -> 0}, {x, -10, 10}, {r, 0, 10}]
May 17, 2013 at 2:23 history edited lagoa CC BY-SA 3.0
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May 17, 2013 at 1:37 history edited lagoa CC BY-SA 3.0
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May 16, 2013 at 23:07 history tweeted twitter.com/#!/StackMma/status/335169731113930753
May 16, 2013 at 18:49 history edited lagoa CC BY-SA 3.0
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May 16, 2013 at 18:37 history edited lagoa CC BY-SA 3.0
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May 16, 2013 at 18:22 history edited lagoa CC BY-SA 3.0
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May 16, 2013 at 17:38 history edited lagoa CC BY-SA 3.0
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May 16, 2013 at 17:34 comment added lagoa This is helpful. It takes 90 seconds now. Thanks!! Other ideas are welcomed.
May 16, 2013 at 16:42 comment added Searke First try: support.wolfram.com/kb/3442 . Esp turn off symbolic processing if speed is an issue.
May 16, 2013 at 14:36 history edited Dr. belisarius
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May 16, 2013 at 14:28 history asked lagoa CC BY-SA 3.0