Timeline for Solving calculation puzzle [closed]
Current License: CC BY-SA 4.0
16 events
| when toggle format | what | by | license | comment | |
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| Feb 15, 2021 at 3:14 | history | closed |
Mariusz Iwaniuk yarchik MarcoB AccidentalFourierTransform Rohit Namjoshi |
Not suitable for this site | |
| Feb 14, 2021 at 20:41 | history | became hot network question | |||
| Feb 14, 2021 at 15:04 | comment | added | MarcoB | Does this answer your question? Find all ways to make 21 by using each of 1, 5, 6 and 7 once, using the four primary binary operations (+, -, *, /) | |
| Feb 14, 2021 at 14:46 | answer | added | Conor Cosnett | timeline score: 6 | |
| Feb 14, 2021 at 13:27 | history | edited | Arji | CC BY-SA 4.0 |
added examples
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| Feb 14, 2021 at 13:21 | comment | added | Arji | Yes. Im gonna edit the question with some examples to make it easier. | |
| Feb 14, 2021 at 13:21 | comment | added | Conor Cosnett | can 7 be used 3 times or 2 times? does it have to be used four times? | |
| Feb 14, 2021 at 13:17 | comment | added | Arji |
I wrote {1,7,7,7,7} instead of {1,7} to express that the number 1 can only be used once and the number 7 can be used four times. So 7*7+7*7+1+1 is not valid.
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| Feb 14, 2021 at 13:05 | comment | added | Daniel Huber | easy: 7*7+7*7+1+1 | |
| Feb 14, 2021 at 13:01 | review | Close votes | |||
| Feb 15, 2021 at 3:14 | |||||
| Feb 14, 2021 at 12:56 | comment | added | J. M.'s missing motivation♦ | Two related questions. | |
| Feb 14, 2021 at 12:53 | history | edited | J. M.'s missing motivation♦ |
edited tags
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| Feb 14, 2021 at 12:53 | comment | added | Arji | You can use each operator as often as you want. | |
| Feb 14, 2021 at 12:51 | comment | added | Conor Cosnett | Do we use each operator only once? | |
| Feb 14, 2021 at 12:43 | comment | added | yarchik | Cool ideas, have you try to implement them? | |
| Feb 14, 2021 at 12:37 | history | asked | Arji | CC BY-SA 4.0 |