Timeline for Numerically evaluating parameter derivatives of a hypergeometric function
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Dec 29, 2020 at 15:00 | history | tweeted | twitter.com/StackMma/status/1343934828786442241 | ||
| Dec 23, 2020 at 18:06 | answer | added | Roman | timeline score: 9 | |
| Dec 23, 2020 at 16:03 | history | became hot network question | |||
| Dec 23, 2020 at 11:31 | answer | added | J. M.'s missing motivation♦ | timeline score: 9 | |
| Dec 23, 2020 at 11:14 | history | edited | J. M.'s missing motivation♦ | CC BY-SA 4.0 |
edited title
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| Dec 23, 2020 at 11:03 | history | edited | J. M.'s missing motivation♦ |
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| Dec 23, 2020 at 9:31 | answer | added | Mariusz Iwaniuk | timeline score: 8 | |
| Dec 23, 2020 at 9:24 | comment | added | cvgmt |
Another dirty workaround. ((Derivative[2, 3, 0, 0][Hypergeometric2F1][0, 1 + t, 2, 1] - Derivative[2, 3, 0, 0][Hypergeometric2F1][0, 1, 2, 1])/t /. t -> 10^-12) // N
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| Dec 23, 2020 at 9:23 | comment | added | Mariusz Iwaniuk |
A dirty workaround: func = (D[ D[Pochhammer[a, k] Pochhammer[b, k]/Pochhammer[c, k]*z^k/ k!, {a, 2}], {b, 4}] // FunctionExpand) /. z -> 1 /. c -> 2 /. b -> 1 // FullSimplify; NSum[ func /. a -> 10^-12, {k, 0, Infinity}]
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| Dec 23, 2020 at 9:20 | comment | added | cvgmt |
It is also curious to me that why we can't calculate the 4-order derivative of the second variable. Only 3-order derivative is OK. Derivative[2, 3, 0, 0][Hypergeometric2F1][0, 1, 2, 1] // N
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| Dec 23, 2020 at 9:20 | comment | added | Mariusz Iwaniuk |
With Maple 2020.2 I have: 291.989096054116602579595642923.
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| Dec 23, 2020 at 9:17 | review | Close votes | |||
| Dec 23, 2020 at 16:55 | |||||
| Dec 23, 2020 at 9:06 | comment | added | AsukaMinato |
Derivative[2, 4, 0, 0][ Hypergeometric2F1][0, 1, 2, 1]
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| Dec 23, 2020 at 8:03 | history | asked | Sachin Kaushik | CC BY-SA 4.0 |