Timeline for How can I add a few specific mesh (altitude-like level) curves to a plot?
Current License: CC BY-SA 4.0
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| Dec 7, 2020 at 19:54 | history | edited | kglr | CC BY-SA 4.0 |
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| Dec 7, 2020 at 18:08 | history | edited | kglr | CC BY-SA 4.0 |
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| Dec 7, 2020 at 17:44 | history | edited | kglr | CC BY-SA 4.0 |
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| Dec 7, 2020 at 17:23 | history | edited | kglr | CC BY-SA 4.0 |
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| Dec 7, 2020 at 16:25 | history | edited | kglr | CC BY-SA 4.0 |
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| Dec 7, 2020 at 15:50 | comment | added | Cham | Agreed. But since my function is a numerical solution, I don't know how to set it up in there. Using Phi[t,#1, #2]& alone doesn't work. With Evaluate, it doesn't work neither, yet. | |
| Dec 7, 2020 at 15:40 | comment | added | kglr |
@Cham, in general, you can use the function in the first argument of ContourPlot as the mesh function. That is, use ContourPlot[foo[x,y], ..., MeshFunctions->{foo[#,#2]&},....] or ContourPlot[foo[x,y], ..., MeshFunctions->{Function[{x,y},foo[x,y]]},....]
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| Dec 7, 2020 at 15:22 | comment | added | Cham | The first method appears to be adapted to the specific function given as an example. I need it to be independent of the function, since the real code is about displaying a numerical solution of some differential equation... | |
| Dec 7, 2020 at 15:22 | history | edited | kglr | CC BY-SA 4.0 |
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| Dec 7, 2020 at 15:03 | history | edited | kglr | CC BY-SA 4.0 |
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| Dec 7, 2020 at 14:58 | history | undeleted | kglr | ||
| Dec 7, 2020 at 14:40 | history | deleted | kglr | via Vote | |
| Dec 7, 2020 at 14:14 | history | edited | kglr | CC BY-SA 4.0 |
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| Dec 7, 2020 at 14:06 | history | answered | kglr | CC BY-SA 4.0 |