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Oct 22, 2020 at 14:24 vote accept Gert
Sep 29, 2020 at 21:51 history became hot network question
Sep 29, 2020 at 18:00 history tweeted twitter.com/StackMma/status/1311002819776966657
Sep 29, 2020 at 16:45 answer added Henrik Schumacher timeline score: 6
Sep 29, 2020 at 15:41 comment added Carl Woll @HenrikSchumacher You should add the MinMax approach as an answer, it is faster than the other answers.
Sep 29, 2020 at 15:13 comment added Michael E2 @HenrikSchumacher I suspect the OP neglected the point because of the use of DeleteDuplicates and the question about "equal elements." I raised it, so that OP might clarify which criterion is desired. (One might want to use Chop or Threshold on max - min in the case of floats depending on how array is calculated.)
Sep 29, 2020 at 15:08 answer added kglr timeline score: 9
Sep 29, 2020 at 15:07 comment added Michael E2 What is the maximum depth of your arrays? Length[DeleteDuplicates[array]] assumes it's depth 1 (a "flat" or non-nested list). MinMax[array] will work with arrays of any depth (vectors, matrices, tensors...).
Sep 29, 2020 at 14:46 comment added Henrik Schumacher @MichaelE2 Good point. Admittedly, I had only the (machine) integer case in mind.
Sep 29, 2020 at 14:29 comment added Michael E2 @Henrik has a good idea but "duplicate" and "equal" mean different things in Mathematica, especially for floating-point numbers and expressions like array = {1 + Sqrt[3], Sqrt[4 + 2 Sqrt[3]]}. An alternative to check duplicates is 0 == Subtract @@ MinMax[array].
Sep 29, 2020 at 14:28 answer added Sjoerd Smit timeline score: 9
Sep 29, 2020 at 14:00 comment added Bob Hanlon Your Length[ DeleteDuplicates[ array ] ] == 1 does not test whether array is constant but rather whether its rows are equal. This is equivalent to Equal @@ array. To test whether array is constant you could use Equal @@ Flatten[array]
Sep 29, 2020 at 13:54 comment added Henrik Schumacher Equal@@MinMax[array] might be a bit faster...
Sep 29, 2020 at 13:47 history asked Gert CC BY-SA 4.0