Timeline for Directional derivative of function at specific point
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Sep 5, 2020 at 0:00 | vote | accept | Teo7 | ||
| Sep 3, 2020 at 10:32 | answer | added | Daniel Huber | timeline score: 2 | |
| Sep 3, 2020 at 7:31 | history | edited | user64494 | CC BY-SA 4.0 |
edited title
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| Sep 3, 2020 at 5:57 | answer | added | user64494 | timeline score: 3 | |
| Sep 3, 2020 at 0:57 | comment | added | A little mouse on the pampas |
Try it:(Grad[x^3/3 - x*y^2 - x/8 + y^2, {x, y}] /. {x -> 1, y -> 1}).Normalize[{Sqrt[3]/2, 1/2}].
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| Sep 2, 2020 at 20:17 | comment | added | Teo7 | @user64494, sorry but I do not understand... how can use this instruction to find the directional derivate? | |
| Sep 2, 2020 at 19:36 | comment | added | flinty |
There's a ResourceFunction: DirectionalD
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| Sep 2, 2020 at 18:25 | comment | added | user64494 |
Here is an example of such sort: {D[Sqrt[RealAbs[x^2 - x*y]], x], D[Sqrt[RealAbs[x^2 - x*y]], y]} /. {x -> 0, y -> 0} produces {Indeterminate, Indeterminate} and D[Sqrt[RealAbs[x^2 - x*y]] /. {x -> t, y -> sqrt[2]*t}, t] /. t -> 0 performs Indeterminate too.
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| Sep 2, 2020 at 18:15 | history | asked | Teo7 | CC BY-SA 4.0 |