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Aug 28, 2020 at 19:01 comment added Daniel Lichtblau I wonder if evaluating 'f' in fixed precision might be better?
Aug 28, 2020 at 13:25 history edited Michael E2 CC BY-SA 4.0
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Aug 28, 2020 at 6:51 vote accept David
Aug 28, 2020 at 4:39 history edited Michael E2 CC BY-SA 4.0
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Aug 28, 2020 at 4:39 comment added Michael E2 @David Thanks, you're question gave me another idea. But see what happens to the precision when you execute NestList[f[#, l[8]] &, 1/2, 2^8]. The precision is reduced as f is nested.
Aug 28, 2020 at 3:34 comment added David Fantastic, thank you. Do you know what's causing a numerical overflow in the lower precision case? It seems like it should be doable without such a high working precision.
Aug 28, 2020 at 2:31 history answered Michael E2 CC BY-SA 4.0