Timeline for Symbolic Matrix Exponential of Large (500x500) Matrix
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Aug 22, 2020 at 17:27 | comment | added | Henrik Schumacher | Indeed. Thank you, @Carl. | |
| Aug 22, 2020 at 17:26 | history | edited | Henrik Schumacher | CC BY-SA 4.0 |
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| Aug 22, 2020 at 17:25 | comment | added | Carl Woll | I think your integration by parts output shouldn’t have d/dt inside the integral | |
| Aug 22, 2020 at 14:08 | comment | added | yarchik | It is probably worth mentioning that the formula you derive is the partial case of the Laplace transform of matrix exponential $\int_0^\infty e^{-ts}e^{tH}\,dt=(sI-H)^{-1}$. Good connection to Green's functions and resolvents. | |
| Aug 22, 2020 at 13:47 | comment | added | Henrik Schumacher | I see. I edited the post. ($dtt$ really looked like a typo.) | |
| Aug 22, 2020 at 13:46 | history | edited | Henrik Schumacher | CC BY-SA 4.0 |
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| Aug 22, 2020 at 11:26 | comment | added | Hugo Andrade | I am sorry. i write it in a cumbersome way. Let me rewrite it, $\int_0^{\infty}t*\frac{d}{dt}<u|exp(-t*H)|v> dt$ | |
| Aug 22, 2020 at 8:28 | history | edited | Henrik Schumacher | CC BY-SA 4.0 |
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| Aug 22, 2020 at 2:39 | comment | added | Hugo Andrade | My matrix $H$ is independent of t. All it's components are real number in the range [0,1] . I need it for every t because i have to evaluate $\int_0^{\infty} dt t \frac{d}{dt} <i| \exp(-Ht)|i_o>$. Due to the form of those vectors, $|i> = {0,0,...1,...0} $ with the $1$ on the $i-th$ component, $<i| \exp(-Ht)|j>$ is the component $ij$-th component of the $\exp(-Ht)$. Is there a way to evaluate just that component and not the hole matrix? | |
| Aug 21, 2020 at 21:17 | history | answered | Henrik Schumacher | CC BY-SA 4.0 |