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Deriving the IDE we get

$$ -n b\psi(b) + c_0 \psi''(b) + (b^2+k)\psi'(b) + 2b\psi(b) = 0 $$

or

$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+b(2-n)\psi(b) = 0 $$ Now if $n < 2,\ \ c_0 > 0,\ \ k > 0$ it looks as an stable ODE.

Follows a possible script to solve the complex case ($\psi = \psi_r+i\psi_i$) according to the comment.

parms = {c0 -> 1/10, k -> -1/10, n -> 13, psir0 -> 14, dpsir0 -> 0, psii0 -> -1, dpsii0 -> 0};
bmax = 10;3;
sol = NDSolve[{c0 psir''[b] + (b^2 + k) psii'[b] + b (n - 2) psii[b] == 0, -c0 psii''[b] + (b^2 + k) psir'[b] + b (n - 2) psir[b] == 0, psir[0] == psir0, psir'[0] == dpsir0, psii[0] == psii0, psii'[0] == dpsii0} /. parms, {psir, psii}, {b, 0, bmax}]
ParametricPlot[Evaluate[{psir[b], psii[b]} /. sol], {b, 0, bmax}]

enter image description here

Deriving the IDE we get

$$ -n b\psi(b) + c_0 \psi''(b) + (b^2+k)\psi'(b) + 2b\psi(b) = 0 $$

or

$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+b(2-n)\psi(b) = 0 $$ Now if $n < 2,\ \ c_0 > 0,\ \ k > 0$ it looks as an stable ODE.

Follows a possible script to solve the complex case ($\psi = \psi_r+i\psi_i$) according to the comment.

parms = {c0 -> 10, k -> 10, n -> 1, psir0 -> 1, dpsir0 -> 0, psii0 -> -1, dpsii0 -> 0};
bmax = 10;
sol = NDSolve[{c0 psir''[b] + (b^2 + k) psii'[b] + b (n - 2) psii[b] == 0, -c0 psii''[b] + (b^2 + k) psir'[b] + b (n - 2) psir[b] == 0, psir[0] == psir0, psir'[0] == dpsir0, psii[0] == psii0, psii'[0] == dpsii0} /. parms, {psir, psii}, {b, 0, bmax}]
ParametricPlot[Evaluate[{psir[b], psii[b]} /. sol], {b, 0, bmax}]

Deriving the IDE we get

$$ -n b\psi(b) + c_0 \psi''(b) + (b^2+k)\psi'(b) + 2b\psi(b) = 0 $$

or

$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+b(2-n)\psi(b) = 0 $$ Now if $n < 2,\ \ c_0 > 0,\ \ k > 0$ it looks as an stable ODE.

Follows a possible script to solve the complex case ($\psi = \psi_r+i\psi_i$) according to the comment.

parms = {c0 -> 1/10, k -> -1/10, n -> 3, psir0 -> 4, dpsir0 -> 0, psii0 -> -1, dpsii0 -> 0};
bmax = 3;
sol = NDSolve[{c0 psir''[b] + (b^2 + k) psii'[b] + b (n - 2) psii[b] == 0, -c0 psii''[b] + (b^2 + k) psir'[b] + b (n - 2) psir[b] == 0, psir[0] == psir0, psir'[0] == dpsir0, psii[0] == psii0, psii'[0] == dpsii0} /. parms, {psir, psii}, {b, 0, bmax}]
ParametricPlot[Evaluate[{psir[b], psii[b]} /. sol], {b, 0, bmax}]

enter image description here

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Deriving the IDE we get

$$ -n b\psi(b) + c_0 \psi''(b) + (b^2+k)\psi'(b) + 2b\psi(b) = 0 $$

or

$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+b(2-n)\psi(b) = 0 $$ Now if $n < 2,\ \ c_0 > 0,\ \ k > 0$ it looks as an stable ODE.

Follows a possible script to solve the complex case ($\psi = \psi_r+i\psi_i$) according to the comment.

parms = {c0 -> 10, k -> 10, n -> 1, psir0 -> 1, dpsir0 -> 0, psii0 -> -1, dpsii0 -> 0};
bmax = 10;
sol = NDSolve[{c0 psir''[b] + (b^2 + k) psii'[b] + b (n - 2) psii[b] == 0, -c0 psii''[b] + (b^2 + k) psir'[b] + b (n - 2) psir[b] == 0, psir[0] == psir0, psir'[0] == dpsir0, psii[0] == psii0, psii'[0] == dpsii0} /. parms, {psir, psii}, {b, 0, bmax}]
ParametricPlot[Evaluate[{psir[b], psii[b]} /. sol], {b, 0, bmax}]

Deriving the IDE we get

$$ -n b\psi(b) + c_0 \psi''(b) + (b^2+k)\psi'(b) + 2b\psi(b) = 0 $$

or

$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+b(2-n)\psi(b) = 0 $$ Now if $n < 2,\ \ c_0 > 0,\ \ k > 0$ it looks as an stable ODE.

Deriving the IDE we get

$$ -n b\psi(b) + c_0 \psi''(b) + (b^2+k)\psi'(b) + 2b\psi(b) = 0 $$

or

$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+b(2-n)\psi(b) = 0 $$ Now if $n < 2,\ \ c_0 > 0,\ \ k > 0$ it looks as an stable ODE.

Follows a possible script to solve the complex case ($\psi = \psi_r+i\psi_i$) according to the comment.

parms = {c0 -> 10, k -> 10, n -> 1, psir0 -> 1, dpsir0 -> 0, psii0 -> -1, dpsii0 -> 0};
bmax = 10;
sol = NDSolve[{c0 psir''[b] + (b^2 + k) psii'[b] + b (n - 2) psii[b] == 0, -c0 psii''[b] + (b^2 + k) psir'[b] + b (n - 2) psir[b] == 0, psir[0] == psir0, psir'[0] == dpsir0, psii[0] == psii0, psii'[0] == dpsii0} /. parms, {psir, psii}, {b, 0, bmax}]
ParametricPlot[Evaluate[{psir[b], psii[b]} /. sol], {b, 0, bmax}]
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Deriving the IDE we get

$$ -n b\psi(b) + c_0 \psi''(b) + (b^2+k)\psi'(b) + 2b\psi(b) = 0 $$

or

$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+(2-n)\psi(b) = 0 $$$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+b(2-n)\psi(b) = 0 $$ Now if $n < 2,\ \ c_0 > 0,\ \ k > 0$ it looks as an stable ODE.

Deriving the IDE we get

$$ -n b\psi(b) + c_0 \psi''(b) + (b^2+k)\psi'(b) + 2b\psi(b) = 0 $$

or

$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+(2-n)\psi(b) = 0 $$ Now if $n < 2,\ \ c_0 > 0,\ \ k > 0$ it looks as an stable ODE.

Deriving the IDE we get

$$ -n b\psi(b) + c_0 \psi''(b) + (b^2+k)\psi'(b) + 2b\psi(b) = 0 $$

or

$$ c_0 \psi''(b) + (b^2+k)\psi'(b)+b(2-n)\psi(b) = 0 $$ Now if $n < 2,\ \ c_0 > 0,\ \ k > 0$ it looks as an stable ODE.

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Cesareo
  • 4k
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