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Jun 10, 2020 at 21:30 vote accept user2799609
Jun 10, 2020 at 20:41 history edited Chris K
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Jun 10, 2020 at 20:40 answer added Chris K timeline score: 2
Jun 10, 2020 at 18:23 comment added user2799609 I fixed the typo for v10. Ideally I would define a function so I could get zeq[ta] for different values of ta. This is a simplification of a more complex model so I need a numerical approach.
Jun 10, 2020 at 18:17 history edited user2799609 CC BY-SA 4.0
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Jun 10, 2020 at 18:10 comment added bbgodfrey ta and v10 are undefined in the code. Also, why not solve for z and x symbolically?
Jun 10, 2020 at 15:50 comment added user2799609 This is a MWE of a host parasite system. x[t] is the host, z[t] is the first generation of parasites and y[t] is the second generation of parasites. ta is longer than the time the host spends in a susceptible developmental stage so when z[t] are produced they need to wait until new susceptible hosts are available in the next time period. When z0 becomes y[T], I don't need the entire history of y[t], just the size at y[T].
Jun 10, 2020 at 15:39 comment added Chris K Hmm, it's more complex than I thought! Could you add some explanation of what you're modeling? When z0 becomes y[T], should it also inherit y[t]'s history?
Jun 10, 2020 at 15:36 comment added user2799609 Yes, I think I do need to restart numerical integration because I need to reset y[0] == 0 and z[0] == z0. (z0 = y[T])
Jun 10, 2020 at 15:32 comment added Chris K It seems that restarting the numerical integration with only t == 0 initial conditions loses the history between iterates then. Do you even need to stop & restart NDSolve?
Jun 10, 2020 at 15:25 comment added user2799609 I want to keep the same ta for all 100 iterates. The goal is to generate lists of y[T] for different values of ta over 100 iterates.
Jun 10, 2020 at 15:20 comment added Chris K To be sure, you want to solve until t == T for a given ta, then change ta and do it again?
Jun 10, 2020 at 14:17 history asked user2799609 CC BY-SA 4.0