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Jul 11, 2021 at 9:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Mar 13, 2021 at 8:06 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Nov 13, 2020 at 8:01 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jul 16, 2020 at 7:02 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jun 16, 2020 at 6:29 answer added user21 timeline score: 1
Jun 9, 2020 at 7:36 comment added xzczd "writing the loop and applying epsilon at any time step is desirable" Why? What you want to do will be done by NDSolve automatically.
Jun 9, 2020 at 7:15 comment added Mohammed I tried item 1 once, but writing the loop and applying epsilon at any time step is desirable. But in the second case, you are right, and I will correct it.
Jun 9, 2020 at 6:52 comment added xzczd Seems that you have some misunderstanding for the basic design of Mathematica. 1. Why not simply Clear[ϵ]; ϵ[x_]=0.01*u[x,t] ? 2. {t, 0, t0, 0.001} is obviously wrong, {t, 0, t0} is the correct one.
Jun 9, 2020 at 6:51 review First posts
Jun 9, 2020 at 13:57
Jun 9, 2020 at 6:46 history asked Mohammed CC BY-SA 4.0