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Mar 24, 2013 at 0:30 comment added Noon Silk rcollyer: Indeed, but I can't do that. Or, put another way, that's equivalent to my original problem :)
Mar 23, 2013 at 23:08 answer added Mr.Wizard timeline score: 3
Mar 23, 2013 at 22:23 answer added Verbeia timeline score: 1
Mar 23, 2013 at 16:22 comment added rcollyer If you can pregenerate the list of integers that will work, then you can use another form of table: Table[...,{i, {list of ints that meet predicate}].
Mar 23, 2013 at 13:39 comment added Noon Silk J. M: Not really, no. The point is it's basically arbitrary; imagine my predicate just randomly returns True when passed an integer.
Mar 23, 2013 at 13:36 comment added Sasha The best way, of course, if you know the mapping from $\mathbb{N}$ to your set. In the toy example you mentioned: 2 Range[Quotient[len,2]], or even Range[2,len,2] does the same as Select[Table[i,{i,len}],EvenQ]
Mar 23, 2013 at 13:35 comment added J. M.'s missing motivation Can you maybe include you actual problem? As I said, there might be structure in your problem that can allow a different solution...
Mar 23, 2013 at 13:34 comment added Noon Silk Haha, indeed J. M. in my actual case the things I want to find are less straightfoward.
Mar 23, 2013 at 13:33 comment added Noon Silk Well, at the moment I can't make such a trade. The Select is slow (I believe) because it creates an inappropriately large array. Do with Reap/Sow also seems unfortunately slow. I was hoping there was a more idomatic (and so hopefully fast) way.
Mar 23, 2013 at 13:32 comment added J. M.'s missing motivation Of course, sometimes problems have a pattern/structure that allow you to do these things more cleverly. In this simple case, you could do Table[2 i, {i, 1, 5}] or Table[i, {i, 2, 10, 2}] for instance; so, exploit patterns when you can!
Mar 23, 2013 at 13:29 comment added J. M.'s missing motivation It's Scylla and Charybdis, I think: you could have it fast, but at the expense of memory, or memory-conserving, but rather slow...
Mar 23, 2013 at 13:27 comment added Noon Silk Yeah; that's basically what I had in mind. Interestingly, it doesn't appear to be particularly fast (though at least it probably doesn't waste memory like the Select option would do ...)
Mar 23, 2013 at 13:13 comment added J. M.'s missing motivation You could use Sow[]/Reap[] with Do[]; e.g. Reap[Do[If[EvenQ[k], Sow[k]], {k, 10}]][[-1, 1]].
Mar 23, 2013 at 13:09 history asked Noon Silk CC BY-SA 3.0