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Mar 30, 2020 at 21:33 vote accept Ely Eastman
Mar 30, 2020 at 20:44 answer added Bob Hanlon timeline score: 4
Mar 30, 2020 at 20:13 comment added JimB If you want the function to be continuous (but not necessarily having the derivative to be continuous) at $t=600$, then you need to have $A \exp \left(-\left(\frac{t-\text{t0}}{\sqrt{2} \sigma }\right)^2\right)=B \exp \left(-\frac{t-\text{t1}}{\tau }\right)$ when $t=600$. That means there will be some restrictions among the parameters. Using Reduce on that equality suggests that using $\tau=-\frac{2 \sigma ^2 (t_1-600)}{2 \sigma ^2 \log \left(\frac{B}{A}\right)+t_0^2-1200 t_0+360000}$ would do it.
Mar 30, 2020 at 19:48 comment added Ely Eastman I need the function to be continuous because I am trying to deconvolve it with another function and want to minimize as much noise as possible in the deconvolution.
Mar 30, 2020 at 19:44 history asked Ely Eastman CC BY-SA 4.0