Timeline for Plotting with known final value [closed]
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
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| Jan 16, 2020 at 12:35 | review | Reopen votes | |||
| Jan 16, 2020 at 14:40 | |||||
| Jan 16, 2020 at 12:17 | history | edited | garej | CC BY-SA 4.0 |
added 67 characters in body
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| Jan 16, 2020 at 1:49 | history | closed |
Michael Seifert MarcoB Alex Trounev m_goldberg NonDairyNeutrino |
Needs details or clarity | |
| Jan 14, 2020 at 16:18 | comment | added | physicsu83 | Yes exactly...Thank you very much. | |
| Jan 14, 2020 at 8:25 | comment | added | garej |
@physicsu83, is that what you need? Plot[Piecewise[{{A3[x], x < 9}, {0, x >= 9}}], {x, -20, 20}, PlotRange -> All, PlotStyle -> Thick, Exclusions -> None]
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| Jan 14, 2020 at 3:02 | comment | added | physicsu83 | Actually, its spin texture which does not exist outside the sphere. It's in spherical co-ordinate, I get A3[R]=0 when Theta=Pi/2 but it will be zero at Rsin(theta) when theta not equal Pi/2. | |
| Jan 14, 2020 at 2:02 | comment | added | Alx |
If you want to just show you plot inside sphere, you can do this like: Plot[A3[x]*Boole[-9<x<9],{x,-20,20}, AxesLabel->{x,z}], or better re-formulate and re-solve your problem so that the solution automatically goes to 0 at the sphere's radius.
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| Jan 13, 2020 at 23:27 | comment | added | Alx |
You can use Boole with some condition to restrict A3 being non-zero in some range: A3[x] Boole[x<=9].
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| Jan 13, 2020 at 23:04 | comment | added | physicsu83 | Hi yes. it's A3[9]=0. Yes, the value at A3[9]=0 is defined, as its the boundary of the sphere in a problem I am trying to solve or we can say that x=R=9 is the radius of the sphere so outside sphere A3[R]=0 | |
| Jan 13, 2020 at 23:01 | history | edited | physicsu83 | CC BY-SA 4.0 |
added 1 character in body
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| Jan 13, 2020 at 20:25 | review | Close votes | |||
| Jan 16, 2020 at 1:49 | |||||
| Jan 13, 2020 at 20:07 | comment | added | Michael Seifert |
Is A3 the same thing as A? What are we allowed to adjust in your equation for A3 to make A3[9] = 0? If the function A3 is what you've shown here, then its value at 9 is completely defined.
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| Jan 13, 2020 at 19:14 | history | edited | Rohit Namjoshi | CC BY-SA 4.0 |
Format code
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| Jan 13, 2020 at 19:11 | comment | added | MarcoB |
A3[x + 7.36521] will have a first zero for $x$ very close to $9$. I found that value using FindRoot[A3[9 + i] == 0, {i, 7.3}].
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| Jan 13, 2020 at 18:35 | history | asked | physicsu83 | CC BY-SA 4.0 |