Timeline for After activating, inactive integral, output is coming same as input
Current License: CC BY-SA 4.0
3 events
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| Oct 21, 2019 at 14:52 | comment | added | Nilabh | Yeah. Integration from 1 to 1 is zero. I have not used inactive integration. When I solved the equation I got this as an output. Do I need to use any function for that | |
| Oct 21, 2019 at 12:34 | comment | added | Alx |
One of your integral is from 1 to 1, so it is zero (?), the second is from 1 to r, but you want plot with {r, 0, 10}. Is everything correct with your s? And general advice not using Inactive[Integrate] (why do you use this?), but use numerical integration with NIntegrate with appropriate bounds: s1[r_?NumericQ]:= ... NIntegrate[...] ....
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| Oct 21, 2019 at 3:15 | history | asked | Nilabh | CC BY-SA 4.0 |