Timeline for Performing a contour integration in Mathematica for a contour starting at $1$ and ending at $-\infty$ while avoiding the origin?
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Jul 20, 2019 at 19:30 | comment | added | sonicboom | I am now back home and have access to Mathematica. It seems it can't evaluate the integral at all now that I have included the logarithmic term. Even just trying to evaluate the indefinite integral is failing, I might have to just try and do it numerically with NIntegrate and plot it instead. | |
| Jul 20, 2019 at 19:23 | comment | added | sonicboom | You are correct, I just realised I am missing a $\frac{1}{2\pi}\log(t)$ in the integral! I will edit my original post. | |
| Jul 20, 2019 at 17:47 | comment | added | Carl Woll | @sonicboom Since your function has no singularity at the origin, why are you trying to 'arc around' it? | |
| Jul 20, 2019 at 17:26 | comment | added | sonicboom | Thanks but the contour actually has to 'arc around' 0, i.e., it has to go from $-\infty$ to $1$ without passing over zero. | |
| Jul 20, 2019 at 14:58 | history | answered | Carl Woll | CC BY-SA 4.0 |