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Jul 23, 2019 at 7:48 history closed m_goldberg
garej
Henrik Schumacher
Öskå
rhermans
Duplicate of Why can't a string be formed by head String?
Jul 23, 2019 at 7:48 comment added rhermans It seems to me that this answer on the question linked by @ lirtosiast explains what the OP needs, so this question has been closed as a duplicate.
Jul 16, 2019 at 3:00 history tweeted twitter.com/StackMma/status/1150963366162288640
Jul 15, 2019 at 23:30 comment added Fortsaint Plus is a function that is defined somewere in the system. Integer is not defined, how can it evaluate to anything if it is not defined!
Jul 15, 2019 at 23:12 history edited MadEmperorYuri CC BY-SA 4.0
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Jul 15, 2019 at 22:53 vote accept MadEmperorYuri
Jul 15, 2019 at 22:52 history edited MadEmperorYuri CC BY-SA 4.0
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Jul 15, 2019 at 22:05 review Close votes
Jul 23, 2019 at 7:50
Jul 15, 2019 at 21:41 comment added Jason B. Related: [How to represent 1 as Symbol[“Integer”]](mathematica.stackexchange.com/q/109639/9490), and Why can't a string be formed by head String?. The accepted answer to the latter is helpful for understanding these types of expressions.
Jul 15, 2019 at 21:36 comment added lirtosiast "Q" at the end of a function signifies it returns True or False e.g. PrimeQ, PalindromeQ.
Jul 15, 2019 at 21:25 answer added Fortsaint timeline score: 1
Jul 15, 2019 at 21:24 answer added John Doty timeline score: 3
Jul 15, 2019 at 21:05 history edited MadEmperorYuri CC BY-SA 4.0
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Jul 15, 2019 at 20:50 comment added bill s Others that you might find interesting to ponder: Head[56] and 56[[0]].
Jul 15, 2019 at 20:47 comment added John Doty You might want to cogitate on the result of AtomQ[56] versus AtomQ[Integer[56]].
Jul 15, 2019 at 20:40 review First posts
Jul 16, 2019 at 0:29
Jul 15, 2019 at 20:39 history asked MadEmperorYuri CC BY-SA 4.0