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May 16, 2019 at 17:08 comment added Alex Trounev @sr101studios It is obvious that u[1/2,y]=u[-1/2,y]=0 and u[x,y]=u[-x,y]=0 at x^2+y^2=1, all this is in DirichletCondition[u[x, y] == 0, True].
May 16, 2019 at 16:40 comment added sr101studios Thank you, Alex! I really appreciate your comments and your updating of the code. The plots looks brilliant. However, I'm not sure how the necessary boundary conditions are being implemented in your example. I think it's important for this system to have the boundary condition u[1/2, y] = u[-1/2, y] and the condition that on the unit circle, u[x,y] = u[-x,y]. However, I'm not sure if your code is implementing those conditions. Do you think it's possible to have boundary conditions like that in our region? Thank you for your help.
May 16, 2019 at 15:07 history answered Alex Trounev CC BY-SA 4.0