Timeline for Selecting matrices based on existence of unique column and row of all equal terms
Current License: CC BY-SA 4.0
15 events
| when toggle format | what | by | license | comment | |
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| May 10, 2019 at 12:12 | comment | added | Rithaniel | Indeed it does. Thank you for the help. | |
| May 10, 2019 at 2:30 | history | edited | ZaMoC | CC BY-SA 4.0 |
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| May 10, 2019 at 2:25 | review | Low quality posts | |||
| May 10, 2019 at 2:50 | |||||
| May 10, 2019 at 2:22 | comment | added | ZaMoC | I believe that now it works | |
| May 10, 2019 at 2:21 | history | undeleted | ZaMoC | ||
| May 10, 2019 at 2:21 | history | edited | ZaMoC | CC BY-SA 4.0 |
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| May 10, 2019 at 2:05 | history | deleted | ZaMoC | via Vote | |
| May 10, 2019 at 2:04 | comment | added | Rithaniel | In that particular situation the correct answer should be the entire input. In both the 4x4 and 5x5 case, the first row and first column are all 1s and 1 is only present in that row/column. | |
| May 10, 2019 at 1:59 | comment | added | ZaMoC | @Rithaniel and? what is the right answer? | |
| May 10, 2019 at 1:56 | comment | added | Rithaniel | Yes, with: {{{3, 3}, {3, 2}}, {{1, 1, 1, 1}, {1, 2, 3, 0}, {1, 0, 0, 0}, {1, 0, 3, 2}}, {{1, 1, 1, 1, 1}, {1, 4, 3, 0, 4}, {1, 3, 3, 3, 0}, {1, 0, 3, 4, 4}, {1, 4, 0, 4, 4}}} it returned: {{{3, 3}, {3, 2}}} | |
| May 10, 2019 at 1:52 | comment | added | ZaMoC | @Rithaniel Did you try it with larger matrices and it didn't work? | |
| May 10, 2019 at 1:47 | comment | added | Rithaniel | Running this returns only 1x1 or 2x2 matrices. What if the list of matrices contain larger matrices, such as 4x4 or 5x5? | |
| May 10, 2019 at 1:35 | review | Low quality posts | |||
| May 10, 2019 at 2:01 | |||||
| May 10, 2019 at 1:28 | history | edited | ZaMoC | CC BY-SA 4.0 |
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| May 10, 2019 at 1:19 | history | answered | ZaMoC | CC BY-SA 4.0 |