Timeline for Why does Arg'[1. + I] return -0.5?

9 events

when toggle format	what		by	license	comment
Apr 25, 2019 at 12:48	history	edited	Roman	CC BY-SA 4.0	added 238 characters in body
Apr 25, 2019 at 9:00	history	edited	Roman	CC BY-SA 4.0	added 382 characters in body
Apr 25, 2019 at 8:50	comment	added	Roman		@Nasser they do give the same result when you apply `N`: `Arg'[1 + I] // N` also gives `-0.5`.
Apr 25, 2019 at 8:48	comment	added	Roman		@xzczd $z$ and $z^$ are independent variables in complex analysis, so $\partial z^/\partial z=0$ etc.
Apr 25, 2019 at 8:47	comment	added	Nasser		Any idea why then `With[{z = 1.0 + I}, Arg'[z]]` not same as `With[{z = 1 + I}, Arg'[z]]`? Should not these give same result?
Apr 25, 2019 at 8:45	comment	added	xzczd♦		Er… how is derivative of $\ln(z^*)$ defined here?
Apr 25, 2019 at 8:36	history	edited	Roman	CC BY-SA 4.0	added 11 characters in body
Apr 25, 2019 at 8:34	history	edited	xzczd♦	CC BY-SA 4.0	Minimal revision.
Apr 25, 2019 at 8:23	history	answered	Roman	CC BY-SA 4.0