Timeline for Vector calculus integration identity problem
Current License: CC BY-SA 4.0
20 events
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| Jun 16, 2020 at 9:23 | history | edited | CommunityBot |
Commonmark migration
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| Apr 25, 2019 at 13:03 | comment | added | xzczd♦ | I think the key point here is to understand the phrase solid angle: mathworld.wolfram.com/SolidAngle.html | |
| Apr 25, 2019 at 0:47 | history | edited | Jose Enrique Calderon | CC BY-SA 4.0 |
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| Apr 1, 2019 at 6:00 | history | tweeted | twitter.com/StackMma/status/1112595589794021377 | ||
| Apr 1, 2019 at 4:16 | history | edited | J. M.'s missing motivation♦ | CC BY-SA 4.0 |
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| Apr 1, 2019 at 4:10 | history | edited | m_goldberg | CC BY-SA 4.0 |
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| Apr 1, 2019 at 3:17 | history | became hot network question | |||
| Apr 1, 2019 at 2:37 | comment | added | Jose Enrique Calderon | @Michael E2 . Yes you are correct. But I I integrate if I am looking for a specific region ie {s,Pi/2, Pi}? | |
| Apr 1, 2019 at 2:33 | history | edited | J. M.'s missing motivation♦ | CC BY-SA 4.0 |
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| Apr 1, 2019 at 2:27 | comment | added | Michael E2 | I've never seen this author's notation. My guess is that $\int_{4\pi}\cdots$ means the integral over the sphere of measure $4\pi$, i.e., the unit sphere. | |
| Apr 1, 2019 at 2:24 | comment | added | J. M.'s missing motivation♦ |
Also to stave off possible questions about entry #5: Integrate[{x, y, z}, {x, y, z} ∈ RegionIntersection[Sphere[], HalfSpace[{0, 0, -1}, 0]]]. Entry #6 would instead use HalfSpace[{0, 0, 1}, 0].
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| Apr 1, 2019 at 2:15 | comment | added | J. M.'s missing motivation♦ | Ah, if you had included the "Let $\hat{s}$ be a unit vector and vectors $A$ and $B$" along with the formula, we would not have needed to guess. ;) | |
| Apr 1, 2019 at 2:15 | vote | accept | Jose Enrique Calderon | ||
| Apr 1, 2019 at 2:13 | answer | added | Michael E2 | timeline score: 6 | |
| Apr 1, 2019 at 2:10 | comment | added | Jose Enrique Calderon | @Michael E2 please post it as an answear for upvote | |
| Apr 1, 2019 at 1:48 | history | edited | Jose Enrique Calderon | CC BY-SA 4.0 |
Add information and references
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| Apr 1, 2019 at 1:37 | comment | added | J. M.'s missing motivation♦ | @Michael, yes, that does seem to be it. This is why people should always define what their variables mean in their formulae. | |
| Apr 1, 2019 at 1:33 | comment | added | Michael E2 |
Here's my guess: With[{s = {x, y, z}, A = {A1, A2, A3}}, Integrate[s (s.A), s \[Element] Sphere[]] ] --- or this: With[{s = {x, y, z}, A = {A1, A2, A3}}, Integrate[s (s.A), s \[Element] Sphere[]] == 4 Pi/3 A ]
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| Apr 1, 2019 at 1:23 | comment | added | J. M.'s missing motivation♦ | What are $s$ and $\omega$ supposed to be? It might be helpful if you can give an example of the textbook with the formula. | |
| Apr 1, 2019 at 1:15 | history | asked | Jose Enrique Calderon | CC BY-SA 4.0 |