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Mar 9, 2019 at 1:19 history edited Michael E2
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Mar 9, 2019 at 0:59 answer added Michael E2 timeline score: 1
Mar 8, 2019 at 0:07 comment added Michael E2 The term linear applied to ODE usually means the equation is linear in the "dependent variables" $y(x)$ and its derivatives, that is, an equation of the form $\sum a_k(x) y^{(k)}(x) = p(x)$; the coefficients $a_k(x)$ and $p(x)$ may be any functions of $x$. Nonlinear equations have dependent variables in nonlinear functions such as $\sin(y(x))$ or x''[z]^2. It seems you are considering only the special case of linear ODES with constant coefficients, not any given ODE such as the one in my comment. That's fine; I just wanted to know since the accepted answer deals only with this special case.
Mar 7, 2019 at 21:57 history edited Taylor Raine CC BY-SA 4.0
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Mar 7, 2019 at 21:57 comment added Taylor Raine @MichaelE2, I have added some clarifications to the question, but generally, if the ODE is non-linear, then the non-linear aspect of the equation should be moved to the RHS of the expression.
Mar 7, 2019 at 21:49 history edited Taylor Raine CC BY-SA 4.0
Clarifications
Mar 7, 2019 at 21:45 comment added Michael E2 What would be the desired form in that case, given that it's nonlinear?
Mar 7, 2019 at 21:38 comment added Taylor Raine @MichaelE2, no, that does not present the format that I am looking for
Mar 7, 2019 at 21:35 vote accept Taylor Raine
Mar 2, 2019 at 0:42 comment added Michael E2 Generalized, including nonlinear equations? E.g. Apply[Equal, Solve[a x'[z] == -b x[z] + c x''[z]^2, {x''[z]}], {2}] -- is it how you'd like?
Mar 2, 2019 at 0:24 history edited m_goldberg CC BY-SA 4.0
Routine cleanup
Mar 1, 2019 at 17:20 answer added march timeline score: 4
Mar 1, 2019 at 16:40 review First posts
Mar 2, 2019 at 0:24
Mar 1, 2019 at 16:38 history asked Taylor Raine CC BY-SA 4.0