Timeline for Converting prefix to infix
Current License: CC BY-SA 4.0
11 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 23, 2019 at 6:33 | vote | accept | ExpressionCoder | ||
| Feb 23, 2019 at 5:56 | vote | accept | ExpressionCoder | ||
| Feb 23, 2019 at 6:33 | |||||
| Feb 23, 2019 at 5:56 | vote | accept | ExpressionCoder | ||
| Feb 23, 2019 at 5:56 | |||||
| Feb 16, 2019 at 9:00 | history | tweeted | twitter.com/StackMma/status/1096695825831526400 | ||
| Feb 12, 2019 at 18:11 | answer | added | Carl Woll | timeline score: 4 | |
| Feb 12, 2019 at 4:40 | history | edited | m_goldberg | CC BY-SA 4.0 |
added 24 characters in body; edited tags
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| Feb 11, 2019 at 21:54 | comment | added | ExpressionCoder | MapAll[Infix, S[a, S[b, c]]] gives Infix[a] ~ S ~ (Infix[b] ~ S ~ Infix[c]) so my remaining question is how to not apply Infix to a, b and c. | |
| Feb 11, 2019 at 21:49 | comment | added | ExpressionCoder | Perhaps via MapAll? But then only applied to non atomic (non leaf) parts? | |
| Feb 11, 2019 at 21:49 | answer | added | kglr | timeline score: 7 | |
| Feb 11, 2019 at 21:43 | comment | added | ExpressionCoder | I noted that Infix[S[Infix[S[a, b]], c]] produces (a ~ S ~ b) ~ S ~ c So it's a matter of nesting the Infix operation in this way. Not sure how to achieve it in Mathematica. | |
| Feb 11, 2019 at 21:40 | history | asked | ExpressionCoder | CC BY-SA 4.0 |